The distance formula is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$ . Let $(x_1,y_1)\rightarrow(5,1)$ and $(x_2,y_2)\rightarrow(3,4)$ , thus:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}$

Therefore, the distance between points P(5,1) and Q(3,4) is $\sqrt{13}$ units.

8 0

3 years ago

A: 2x + 8y = 5 B: x + 9y = 10

zalisa [80]

Hope this helps you!

3 0

3 years ago

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Sveta_85 [38]

Answer:

ill answer if u can make it english

Step-by-step explanation:

6 0

3 years ago

Pleases solve this. I need help! At least the slope! Giving 75 points!

masha68 [24]

Answer:

Slope is 1/2. Used points 0,0 & 6,3

Step-by-step explanation:

7 0

2 years ago

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