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2 years ago

Are some integers irrational

2 answers:

5 0

Answer:In other words, a number is rational if we can write it as a fraction where the numerator and denominator are both integers. ... Irrational, then, just means all the numbers that aren't rational. Every integer is a rational number, since each integer n can be written in the form n/1.

Step-by-step explanation:

klemol [59]2 years ago

4 0

What are the options?

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You have $30 to buy muffins. However, at the shop you can buy 1 muffin for $4. (a) Write an inequality from the above informatio

sattari [20]

Answer:

Let m be the number of muffins.

a) 4m <= 30

b) m <= 7.5, so the maximum number of muffins to buy is 7.

c) $4 × 7 = $28, so $2 will be left over.

8 0

1 year ago

What is the value of x in the solution to this system of equations?

liberstina [14]

Answer:

x = 11

Step-by-step explanation:

Given the expression;

5x+2y=67 ...1

x=3y−7 ....2

Substitute 2 into 1

5(3y-7)+2y = 67

15y - 35 + 2y = 67

17y = 67+35

17y = 102

y = 102/17

y =6

Recall that x = 3y - 7

x = 3(6) - 7

x = 18 - 7

x = 11

Hence the value of x is 11

6 0

2 years ago

Examine the work shown. Explain the error and find the correct result.

wlad13 [49]

Answer:

= 6

Step-by-step explanation:

in the third step, they did 2 x -12 and got 24. It should’ve been -24 since it was a positive times a negative. It shouldve been

-24 - (-30)

-24 + 30

= 6

6 0

2 years ago

-7x + -2x<br> U gotta combine the like terms

NNADVOKAT [17]

Answer:

-9x

Step-by-step explanation:

-7x + -2x

Factor out the x

x(-7-2)

x(-9)

-9x

3 0

2 years ago

Read 2 more answers

5. Solve using any method.<br> y = -x + 8<br> y=x+4

vlada-n [284]

Answer:

Step-by-step explanation:

$\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

$\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

7 0

2 years ago