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Cloud [144]
3 years ago
14

The length of rectangle is 1 meter less than it's width . The area of the rectangle is 42 square meters. Find the dimensions of

the rectangle.
Mathematics
1 answer:
serg [7]3 years ago
7 0
We can turn this word problem into equations! So let l be length and w be width. So we can write, l+1=w. And l*w=42. we can plug the first equation in... l(l+1)=42 which is l^2+l=42. We can see that l=6. So w=7.
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Change 20 5/9 to an<br> improper fraction.
RideAnS [48]

Answer:

185/9

Step-by-step explanation:

20 5/9

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Add the 5 (the numerator) to 180, and you'll get 185.

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Well I'm having troubles with something I have no idea what it is or how to do it. The problem is x^2 -18x+8=0. I only know how
Lubov Fominskaja [6]

Answer:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

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Step-by-step explanation:

We have the following equation:

x^2 -18 x +8 =0

We can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where:

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And replacing we got:

x = \frac{-(-18) -\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 -2 \sqrt{73}}{2}= 9 -\sqrt{73}

x = \frac{-(-18) +\sqrt{(-18)^2 -4*1*8}}{2} = \frac{18 +2 \sqrt{73}}{2}= 9 +\sqrt{73}

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Texting speed

Step-by-step explanation:

It's the dependent variable

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Answer:

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