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3 years ago

Is there a difference between the 80th percentile and the top 80%?

1 answer:

8 0

Actually, yes there is. Being in the 80th percentile means that you are smart than 80% of the people (i.e. out of 100 people, you would be smarter than 80 of them). However being in the top 80% means that you are a part of the 80 smartest people out that same 100.

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Roll a dice. Chance of it landing on a 6 is ? In ?

ohaa [14]

It is a 1 to 6 ratio

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3 years ago

Read 2 more answers

Zahir made this wooden perch for his pet bird. What is the volume of the bird perch? Round to the nearest tenth if necessary.

Nonamiya [84]

Answer:

675

Step-by-step explanation:

3 0

3 years ago

Please help me I tried to do it

anyanavicka [17]

You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277
so if i did it right you should get n=277

8 0

3 years ago

use the line graph to answer the question 9 and 10 how much did the temperature change from Sunday High to Mondays High ? what w

Marizza181 [45]

Answers:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

Explanation:

Taking into account the graph, we get that the high temperature each day is:

Sunday: -10°C

Monday: -6 °C

Tuesday: - 4 °C

Wednesday: -6 °C

Thursday: 0 °C

Friday: 4 °C

Saturday: -2 °C

So, the change from Sunday High to Mondays High can be calculated as:

Change = Monday - Sunday

Change = -6 °C - (- 10 °C)

Change = -6 °C + 10 °C

Change = 4 °C

In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:

Difference = Friday - Wednesday

Difference = 4 °C - (-6 °C)

Difference = 4 °C + 6 °C

Difference = 10 °C

Therefore, the answers are:

How much did the temperature change from Sunday High to Mondays High?

Change = 4 °C

What was the difference between the high temperatures on Friday and Wednesday?

Difference = 10 °C

6 0

1 year ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago