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nadya68 [22]
4 years ago
6

Regina, Phil and Joseph each wrote expressions to represent their hourly earnings for an after-school job where h represents the

number of hours worked. Regina: 6.50h + 16 Phil: 3(2.5h + 5) Joseph: 7.50h + 10 How many hours will Regina and Phil have to work in order to make the same amount of money in one week? Show your work.
Mathematics
1 answer:
Citrus2011 [14]4 years ago
7 0

Answer:

h=-15, -15 hours is your answer. You can't work negative hours though which means that Regina and Phil will never be able to make the same amount.

Phil has a higher rate and starting value, this means that Regina will never make the same amount working the same hours.

Step-by-step explanation:

Regina: 6.5h

Phil: 3(2.5h+5)

When you plug in the number of hours, you get the weekly pay.  In order to get the same weekly pay, set the equations equal to each other.

6.5h=3(2.5h+5), This is an equation to find the number of hours it will take for them to get equal pay. Now, simplify.

6.5h=7.5h+15

-h=15

h=-15, -15 hours is your answer. You can't work negative hours though which means that Regina and Phil will never be able to make the same amount.

Phil has a higher rate and starting value, this means that Regina will never make the same amount working the same hours.

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Question 2:
Ugo [173]

With the frequecy distribution shown in the 50 cities of pakistan,

  • range = 18
  • mean = 18.1
  • median = 19.8333
  • mode = 19.125
  • kurtosis = 2.7508
  • Standard deviation = 3.75

<h3>How to find the Range</h3>

= highest value - lowest value

= 26.5 - 8.5

= 18

<h3>How to find the mean</h3>

= ∑ f x / ∑ f

= ∑ f x / N

= 905 / 50

= 18.1

median

= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )

C = cumulative frequency preceeding to the median class frequency

h = class interval

= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18

= 18.5 + 1.3333

= 19.8333

<h3>How to find the mode</h3>

The mode is the value with the highest frequency occurence. This is under class 18 - 20

mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h

f1 = fequency of the modal class

f0 = freqency of the preceeding modal class

f2 = frequency of the next modal class

h = class interval

= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 )  ) * 3

= 18 + ( 0.375 ) * 3

= 19.125

<h3>How to find the standard deviation </h3>

= sqrt ( 1 / N ∑ f ( x - x' )^2 )

= sqrt (1  / 50 * 706.5

= 3.7589

<h3>How to solve for relative dispersion </h3>

=  standard deviation / mean

= 3.7589 / 3

= 1.2530

<h3>What is the variance? </h3>

= ( standard deviation )^2

= ( 3.7589 )^2

= 14.1293

<h3>How to solve for kurtosis</h3>

=  ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )

= 27459.405 / ( 50 * 3.7589^4 )

= 2.7509

Read more on frequency distribution here: brainly.com/question/1094036

4 0
2 years ago
Find the value of x. Round the answer to the nearest tenth if needed.
horrorfan [7]
I hope this helps you

8 0
4 years ago
M/-5 = 4 one or two step equation
lana [24]

Answer:

I think it is one-step because when solving it all you have to do is multiply -5 by -5 to get the answer. m= -20

8 0
3 years ago
Please help me with word problems
barxatty [35]

Answer:

Step-by-step explanation:

.16x + 22.92 = 25.00

.16x = 2.08

x = 13 yards of ribbon

7 0
2 years ago
-6x-6y =18 6x-3y=27 its supposed to be solving systems by elimination by adding or subracting, im really confused.
Lera25 [3.4K]

Answer:

y = -5

x = 2

Step-by-step explanation:

The computation is show below:

Given that

-6x - 6y = 18

6x - 3y = 27

Now if we solved both equation so

-9y = 45

y = -5

And, x is

-6x - 6(-5)  = 18

-6x + 30 = 18

-6x = 18 - 30

-6x = -12

x = 2

3 0
3 years ago
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