Question 2:
1 answer:
With the frequecy distribution shown in the 50 cities of pakistan,
- range = 18
- mean = 18.1
- median = 19.8333
- mode = 19.125
- kurtosis = 2.7508
- Standard deviation = 3.75
= highest value - lowest value
= 26.5 - 8.5
= 18
<h3>How to find the mean</h3>= ∑ f x / ∑ f
= ∑ f x / N
= 905 / 50
= 18.1
median
= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )
C = cumulative frequency preceeding to the median class frequency
h = class interval
= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18
= 18.5 + 1.3333
= 19.8333
<h3>How to find the mode</h3>The mode is the value with the highest frequency occurence. This is under class 18 - 20
mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h
f1 = fequency of the modal class
f0 = freqency of the preceeding modal class
f2 = frequency of the next modal class
h = class interval
= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 ) ) * 3
= 18 + ( 0.375 ) * 3
= 19.125
<h3>How to find the standard deviation </h3>= sqrt ( 1 / N ∑ f ( x - x' )^2 )
= sqrt (1 / 50 * 706.5
= 3.7589
<h3>How to solve for relative dispersion </h3>= standard deviation / mean
= 3.7589 / 3
= 1.2530
<h3>What is the variance? </h3>= ( standard deviation )^2
= ( 3.7589 )^2
= 14.1293
<h3>How to solve for kurtosis</h3>= ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )
= 27459.405 / ( 50 * 3.7589^4 )
= 2.7509
Read more on frequency distribution here: brainly.com/question/1094036
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To find 1,188 divided by 12. I think about 1,200 divided by 12 that's groups 100 of 12. 1,188 has fewer group of 12
Answer: If we divide 1200 by 12, we will get 100 12's in 1200.
But our question is 1188 divided by 12.
So the difference between 1200 and 1188 is 12. Therefore there will be 99 12's in 1188.
Therefore, 1188 divided by 12 is 99.
Also I have shown in the image attached how 1188 divided by 12 is 99.
