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3 years ago

When you are working on an unsaved document on a PC, where is the document temporarily saved?

Computers and Technology

1 answer:

Serga [27]3 years ago

3 0

Answer:

RAM

Explanation:

RAM or Random Access Memory is a volatile storage memory which means if a power is turned off and turned on again it will be clear, that is why, if we do not save our work and a power failure occurs, our data is lost. It is where all our running programs are located while we are working. There is another memory, which is ROM(Read Only Memory). This is a non-volatile storage and saved work is stored in ROM.

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How can presentation software be used in a business or professional setting? Choose all that apply.

ahrayia [7]

Answer:

Presentations are commonly projected onto a whiteboard a large screen.

Slides can also be printed out onto clear acetate and used with a overhead projector (0HP) to project the contact onto a screen. If this method is used each acetate side usually has to be replaced my newly.

Presentations can also be set up to play through a large did you go display in reception areas of the hotels, schools, businesses etc.

3 0

4 years ago

Which of the following is least likely to be a scientific experiment?

enot [183]

It would be the last one, because she isn't recording any type of data over what she is doing and she isn't observing it at all. She simply trimmed the stems of a bouquet of flowers. However, the other options insist that they are recording data and observing, like you would do when performing an experiment. I hope this helps! :)

8 0

3 years ago

Read 2 more answers

The maximum-valued element of an integer-valued array can be recursively calculated as follows: If the array has a single elemen

Tasya [4]

Solution :

#include <iostream>

using namespace std;

//Function Declaration

int max(int arr[],int size);

int main()

{

//Declaring variable

int size;

while(true)

{

cout<<"Enter the no of elements in the array :";

cin>>size;

if(size<=0)

{

cout<<"Invalid.Must be greaterthan Zero"<<endl;

continue;

}

else

break;

}

//Creating an array

int arr[size];

/* getting the inputs entered by

* the user and populate them into array

for(int i=0;i<size;i++)

{

cout<<"Enter element#"<<i+1<<":";

cin>>arr[i];

}

//calling function

int maximum=max(arr,size);

//Displaying the output

cout<<"The maximum Element in the Array is :"<<maximum<<endl;

return 0;

}

/* Function implementation which finds

* the maximum element in the array and return it

int max(int arr[],int size)

{

//Declaring the static variables

static int k=0,maximum=-999;

/* This if block will execute only if the value of k

* is less than the size of an array

if(k==size-1)

{

return arr[0];

}

else if(size-1>k)

{

if(arr[k]>maximum)

maximum=arr[k];

//Incrementing the k value

k++;

//Calling the function

max(arr,size);

}

return maximum;

}

4 0

3 years ago

Java

VARVARA [1.3K]

Answer:

Here are the two statements which use nextInt() to print two random integers between 0 and 9:

System.out.println(randGen.nextInt(10));

Explanation:

Here is the complete program:

import java.util.Scanner; //to accept input from user

import java.util.Random; // use to generate random numbers

public class DiceRoll { //class definition

public static void main (String [] args) {//start of main function

Random randGen = new Random(); // creates a Random class object randGen

int seedVal = 0; //sets starting point for generating random numbers

randGen.setSeed(seedVal); //sets the seed of random number generator

System.out.println(randGen.nextInt(10)); //generates and prints the first random integer between 0 and 9 (10 is the range from 0 to 9) using nextInt method, which is used to get next random integer value from the sequence of random number generator

System.out.println(randGen.nextInt(10)); //generates and prints the second random integer between 0 and 9 (10 is the range from 0 to 9) using nextInt method

return; } }

Another way to write this is to initialize two int variables:

int integer1;

int integer2;

Now use two print statements to print these random integers between 0 and 9 as:

System.out.println(integer1= randGen.nextInt(10));

Another way to write this is:

Set the value of integer1 to a random number from 0 to 9 and same for integer2

int integer1 = randGen.nextInt(10);

int integer2 = randGen.nextInt(10);

Now use two print statements to print these random integers between 0 and 9 as:

System.out.println(integer1);

System.out.println(integer2);

5 0

3 years ago

Which of the following are actions a programmer could take when debugging a segment of code that would most likely lead to findi

Verizon [17]

Answer:

Option B and C are the correct answer for the above question

Explanation:

The above question asked about the work of the programmer to catch an error of the program--

Then the option B states that the programmer needs to prints the value of the various program variable on every line of the program which is the correct solution because it is used to find the error easily. It defines the value of every variable in every place of the program and the programmer caught the error statement in the program if anywhere the variable gets the false value.
The C option states to help from a friend, it is also a good solution because the friend can easily be caught the error of the program by seeing every line of code.
But the other option is not correct because the option A states that the change the name of the variable which is not a result of anything.
And the option D states that the code will be retyped again which is also not justify anything.

6 0

3 years ago