Answer:
The first value of i is 0 and last value of i is 20.
Explanation:
The following are the description of a given loop.
- In this problem, there are two loops one is the internal loop and the other is the external loop
- In the outer loop, the value of " i" is initialized with "0" So the first value is printed 0 in the console.
- For one value of "i" all the inner loop is executed.
- The loop is executed is less equal to 20 that's why the last value of "i" is printed 20 in the console window.
A server stopped provide service to 100 users
Answer:
Best: 1 or 4
Worst: 3
Explanation:
I'm not sure if number one is imply to ask your coworker to explain it or actually help with the workload. I think 4 would be the right answer because that is what they are there for and you don't want to distract your coworkers.
Answer:
The system that will be more prone to attack or vulnerability is the bank that has ten branches spread throughout California with the data being stored on a mainframe in San Francisco.
Explanation:
Solution
If the databases are not shared by all the branches throughout the network, they could not be hacked or accessed easily. but when the systems are in a network and share databases or resources,then these could be more vulnerable to unauthorized persons or individuals.
The data been stored on a mainframe in San Francisco that is a centralized access by 10 branches of another bank. what this implies is that networking is involved or used to share data.
With this example, the chances of vulnerability or attacks increases from the following :
- Accounts payable could be disturbed by changing cash in payment false.
- Entering incorrect data into the system. such transactions can be altered, deleted by unauthorized persons.
- Transaction fraud like hacking, masquerading are very common in a networked system.
The fraction of shipments that will be accepted is 0.1299.
<h3>
How to calculate the probability?</h3>
Probability of a defective DVD = 0.04
Using Binomial distribution,
Fraction of shipments accepted = Probability of zero defects in sample of 50 = P(X = 0)
= 50C0 * 0.040 * (1 - 0.04)⁵⁰
= 0.96⁵⁰
= 0.1299
Fraction of shipments accepted = Probability of zero or one defects in sample of 50 = P(X = 0) + P(X = 1)
= 50C0 * 0.040 * (1 - 0.04)50-0 + 50C1 * 0.041 * (1 - 0.04)50-1
= 0.9650 + 50 * 0.04 * 0.9649
= 0.4005
Learn more about probability on:
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