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3 years ago

2மP-* =+ எனின் P++ 0gm

Mathematics

1 answer:

Sholpan [36]3 years ago

3 0

Answer:

Suppp. Broooo

Step-by-step explanation:

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Write the equation of a line that is parallel to {x=8}x=8x, equals, 8 and that passes through the point {(-3,-2)}(−3,−2)left par

Alexxandr [17]

Answer:

x = -3

Step-by-step explanation:

The line parallel to x=8 is another vertical line:

x = constant

To make it go through a point with an x-coordinate of -3, the constant must be -3.

Your line is ...

x = -3

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4 years ago

4) A window is in the form of a rectangle surmounted by a semicircle. The rectangle is of clear glass, whereas the semicircle is

lisov135 [29]

Answer:

l=0.1401P\\

w =0.2801P

where P = perimeter

Step-by-step explanation:

Given that a window is in the form of a rectangle surmounted by a semicircle.

Perimeter of window =2l+\pid/2+w

$P= 2l+3.14 (w/2)+w$

Or $P = 2l+2.57w\\l = \frac{P-2.57w}{2}$

To allow maximum light we must have maximum area

Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle

$A=lw +\pi \frac{w^2}{8}$

$A=lw +\pi \frac{w^2}{8}\\A=w*\frac{P-2.57w}{2}+0.3925w^2\\2A= Pw-2.57w^2+(0.785w^2)\\2A' = P-5.14w+1.57 w\\2A" =-5.14+1.57$

Hence we get maximum area when i derivative is 0

i.e. $P-5.14w+1.57 w=0\\3.57w =P\\w = \frac{P}{3.57} =0.2801P$

$l = \frac{P-2.57w}{2}\\l = 0.1401P$

Dimensions can be

$l=0.1401P\\w =0.2801P$

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3 years ago

Find the solutions to sin2(x) + cos(x) = 1, keeping 0 ≤ x < 2π

frozen [14]

Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}

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3 years ago

Find the measure of angle x in the figure below<br>67 61<br>у<br>X<br>67

kondor19780726 [428]

Answer: y67

Step-by-step explanation:5n − 19 + n + 7 = 144 − 6n

6n − 12 = 144 − 6n

12n = 156

n = 13

m∠z = (144−6n)°

m∠z = (144−6×13)°

m∠z = y67

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3 years ago

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Which choice represents the expression below as a single exponential

Lostsunrise [7]

Answer:

Step-by-step explanation:

When multiplying numbers with the same base but different exponents, add the exponents together.

4 0

2 years ago

2மP-* =+ எனின் P++ 0gm​

2மP-* =+ எனின் P++ 0gm