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4 years ago

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Bao has been notified by his electric company that his rates are going up on his graduated fee schedule. He currently pays: Stan

dard Use Plan 6.5 cents/kWh for the first 600 kWh 12 cents/kWh for the next 600 kWh If his rates go up 1 cent in each category, find how much he will pay if he uses 875 kWh per month. Round to the nearest dollar. a. $72 b. $105 c. $66 d. $81

2 answers:

Dafna1 [17]4 years ago

7 0

<span>1)Consumption: 875 kWh / month

2) New rate:

- 7.5 cents / kWh for the first 600 kWh
- 13.0 cents / kWh the next 600 kWh

3) Calculation:

600 kWh * 7.5 cents/ kWh + (875 kWh - 600 kWh) * 13.0 cents / kWh.

4500 cents + 3575 cents = 8075 cents = $ 80.75, which rounded to the nearest dolar is $ 81.

Answer: option d. $81.
</span>

Lapatulllka [165]4 years ago

7 0

Answer:

$81

Step-by-step explanation:

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3 years ago

Each student needs a pencil and a eraser to take a test.If pencils come in 8 in a box and erasers come 12 in a bag, what is te l

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<u><em>Explanation</em></u>

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As there are total 24 students and each student needs one pencil and one eraser to take a test, so...

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3 years ago

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3 years ago

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Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

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Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

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$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

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also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

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3 years ago