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krok68 [10]
3 years ago
7

Pablo generates the function f(x) = 3/2(5/2)^x-1 to determine the x'th number in a sequence.

Mathematics
2 answers:
Masteriza [31]3 years ago
6 0

Answer:

The. answer. is. A

Step-by-step explanation:

BaLLatris [955]3 years ago
5 0

Answer:

A.

f(x+1)=5/2f(x) with f(1)=3/2

Step-by-step explanation:

So we are looking for a recursive form of

f(x)=\frac{3}{2}(\frac{5}{2})^{x-1}.

This is the explicit form of a geometric sequence where r=5/2 and a_1=\frac{3}{2}.

The general form of an explicit equation for a geometric sequence is

a_1(r)^{n-1} \text{ where } a_1 \text{ is the first term and } r \text{ is the common ratio}.

The recursive form of that sequence is:

a_{n+1}=ra_n \text{ where you give the first term value for } a_1.

So we have r=5/2 here so the answer is A.

f(x+1)=5/2f(x) with f(1)=3/2

By the way all this says is term is equal to 5/2 times previous term.

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