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Vika [28.1K]
3 years ago
14

Work out the area of this trapezium 6cm 10cm 8cm 17cm

Mathematics
1 answer:
sasho [114]3 years ago
5 0

Answer:

  (81√15)/4 ≈ 78.43 cm²

Step-by-step explanation:

It can help to draw a diagram.

The base angle at the side of length 6 can be found using the Law of Cosines. Its opposite side is of length 8, and the two adjacent sides are of length 6 and 7. So, we have ...

  8² = 6² +7² -2·6·7·cos(α)

  cos(α) = (36+49-64)/(84) = 1/4

  α = arccos(1/4) ≈ 75.522°

Then the height of the trapezium is ...

  6·sin(75.522°) ≈ 5.80948 . . . . cm

__

The area of the trapezium is given by the formula ...

  A = 1/2(b1 +b2)h

  A = (1/2)(17 +10)(5.80948) . . . . cm²

  A ≈ 78.43 cm²

__

Of course, sin(arccos(1/4)) = (√15)/4, so the exact formulation of the area is ...

  A = (81√15)/4 cm²

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Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16
IrinaK [193]

Answer:

Jogging 6th time.

Step-by-step explanation:

We have been given that Vicki started jogging the first time she ran she ran 3/16 mile the second time she ran 3/8 mile and the third time she ran 9/16 mile.

We can see that the distance Vicki covers each time forms a arithmetic sequence, where 1st term is 3/16.

We know that an arithmetic sequence is in form a_n=a_1+(n-1)d, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

n =  Number of terms in sequence,

d = Common difference.

Let us find common difference of our given sequence as:

\frac{3}{8}-\frac{3}{16}\Rightarrow \frac{6}{16}-\frac{3}{16}=\frac{3}{16}

Since Vicki needs to cover more than 1 mile, so we nth term of sequence should be greater than 1.

1

Let us solve for n.

1

1

1\cdot \frac{16}{3}

5.333

n>5.333

We can also write next terms of our sequence as:

\frac{3}{16},\frac{6}{16}, \frac{9}{16},\frac{12}{16},\frac{15}{16},\frac{18}{16}

Therefore, Vicki will run more than 1 mile when she is jogging for 6th time.

7 0
3 years ago
The length of a rectangle is 3 times the width. If the perimeter is to be greater than 56 meter. What are the lossible values fo
lidiya [134]

Answer:

w > 7

Step-by-step explanation:

L = 3w

2L + 2w > 56

sub for L

2(3w) + 2w > 56

6w + 2w > 56

8w > 56

w > 7


Check: L = 3(8)

L = 24

2(24) + 2(8) > 56

48 + 16 > 56

64 > 56

7 0
3 years ago
Read 2 more answers
Help picture below problem 13
kirza4 [7]

The Pythagorean theorem is the idea that the sum of the two legs which are both squared is equal to the hypotenuse's length squared.

     *<em>look at the image I attached for a better explanation</em>

By looking at the picture, we are missing the leg's length, and by using the Pythagorean theorem, we get the equation

    ?^2+5^2 = 13^2\\?^2 + 25 = 169\\?^2 = 144\\? = 12

Thus the <u>missing side length is 12 cm</u>

Hope that helps!

8 0
3 years ago
What is the answer to 2x-3over 4 +5=3x
SVETLANKA909090 [29]

<em>x </em>= 17

___

10 something like that, but closer together. LOL sorry!!

6 0
4 years ago
Hurry pleaseeee taking a test Which expression is equivalent to 30°? Inverse of cosine (StartFraction StartRoot 3 EndRoot Over 2
nika2105 [10]

Answer:

Inverse of cosine (StartFraction StartRoot 3 EndRoot Over 2 EndFraction)

Step-by-step explanation:

According to trigonometry identity;

Cos 30° = √3/2

To get the expression equivalent to 30°, we will take the inverse of both sides as shown;

Cos^-1(cos 30°) = cos^-1(√3/2)

The arccos will cancel out the cos on the left hand side of the equation to have;

30° = cos^-1(√3/2)

Hence 30° is equivalent to inverse of cosine of √3/2 or Inverse of cosine (StartFraction StartRoot 3 EndRoot Over 2 EndFraction)

8 0
3 years ago
Read 2 more answers
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