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Free_Kalibri [48]
3 years ago
13

Solve the equation 2 cos ( x ) + 1 = 0 2 cos x + 1 = 0 , 0 ≤ x ≤ 2 π 0 ≤ x ≤ 2 π . Show all of your work

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0

Answer:

2π/3, 4π/3

Step-by-step explanation:

I interpret your question as asking us to solve the equation

2cos(x) + 1 = 0

2cos(x) = -1

cos(x) = -½x  

x = arccos(-½), 0 ≤ x ≤2π

Since the cosine is negative, x must be in the second or third quadrant.

Referring to the unit circle, we find that

x = 2π/3 (120°) or x = 4π/3 (240°)

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aniked [119]

Answer:

The equation of the line is:

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Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

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Given

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now substituting b = -12 and m = 3/2 in the slope-intercept form of line equation

y = mx+b

y\:=\:\frac{3}{2}x\:+\:\left(-12\right)

y\:=\:\frac{3}{2}x\:-12

Therefore, the equation of the line is:

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8 0
3 years ago
Which student's work is correct? Explain please
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Step-by-step explanation:

Wendy

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8 0
3 years ago
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jok3333 [9.3K]

Answer:

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Written equivalent inequality:

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Multiply both sides by 4. Since 4 is positive, the inequality direction remains the same.

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I hope this helps you!! :)

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