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Alika [10]
4 years ago
6

a satellite with a geostationary orbit travels at a constant speed of 1676401km/h if it takes the satellite 24 hours to revolve

around the earth once what is the distance of the path the satellite travels
Physics
1 answer:
AlexFokin [52]4 years ago
6 0
This "1676401km/h" can't be right. A geostationary satellite orbits at <span>3.07 km/s, or 11,052 km/h.

Okay, the problem is done like this:

2*pi*D = speed * 24 h, if you plug your </span>1676401km/h:

2pi*D = 1676401*24 ---> D  = 6,403,365 km

But again you should make sure what the speed is in the statement. Best!

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Match the events related to the formation of the universe with the stages during which they occurred.
igomit [66]

Answer:

does this even make sense

Explanation:

8 0
3 years ago
Which term describes an educated guess about the outcome of an
bezimeni [28]

Answer:

Hypothesis

Explanation:

Refer to a trial solution to a problem as a hypothesis, often called an "educated guess" because it provides a suggested outcome based on the evidence.

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3 years ago
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Two buses are driving along parallel freeways that are 5mi apart, one heading east and the other heading west. Assuming that eac
Oksanka [162]

Answer:

101.54m/h

Explanation:

Given that the buses are 5mi apart, and that they are both driving at the same speed of 55m/h, rate of change of distance can be determined using differentiation as;

Let l be the be the distance further away at which they will meet from the current points;

l=\sqrt{13^2-5^2}=12m\\\\\frac{dl}{dt}=-(55m/h+55m/h})\\\\=-110m/h#The speed toward each other.

\frac{dh}{dt}=0, \ \ \ \ h=constant\\\\h^2+l^2=b^2\\\\2h\frac{dh}{dt}+2l\frac{dl}{dt}=2b\frac{db}{dt}\\\\2\times5\times0+2\times12\times(-110)=2\times13\frac{db}{dt}\\\\\frac{db}{dt}=-101.54m/h

Hence, the rate at which the distance between the buses is changing when they are 13mi apart is 101.54m/h

4 0
3 years ago
the ratio of the energy per second radiated by the filament of a lamp at 250k to that radiated at 2000k, assuming the filament i
Naily [24]

Answer:

(a) \frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b) P =  0.816 Watt

Explanation:

(a)

The power radiated from a black body is given by Stefan Boltzman Law:

P = \sigma AT^4

where,

P = Energy Radiated per Second = ?

σ = stefan boltzman constant = 5.67 x 10⁻⁸ W/m².K⁴

T = Absolute Temperature

So the ratio of power at 250 K to the power at 2000 K is given as:

\frac{P_{250k}}{P_{2000k}}=\frac{\sigma A(250)^4}{\sigma A(2000)^4}\\\\\frac{P_{250k}}{P_{2000k}}=2.4\ x\ 10^{-4}

(b)

Now, for 90% radiator blackbody at 2000 K:

P = (0.9)(5.67\ x\ 10^{-8}\ W/m^2.K^4)(1\ x\ 10^{-6}\ m^2)(2000\ K)^4

<u>P =  0.816 Watt</u>

7 0
3 years ago
If an atom has an atomic number of 2, it will be stable with 2 electrons in its valence shell. Group of answer choices True Fals
torisob [31]

Answer: True

Explanation:

Atomic number is defined as the number of protons or the number of electrons that are present in an electrically neutral atom.

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The electronic configuration will be 1s^2

As its duplet is already complete and it has noble gas configuration , it is stable with 2 valence electrons.

3 0
3 years ago
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