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dsp73
3 years ago
13

A volumetric flask made of Pyrex is calibrated at 20.0°C. It is filled to the 150-mL mark with 34.5°C acetone. After the flask i

s filled, the acetone cools and the flask warms so that the combination of acetone and flask reaches a uniform temperature of 32.0°C. The combination is then cooled back to 20.0°C. (The average volume expansion coefficient of acetone is 1.50 10-4(°C)−1.) (a) What is the volume of the acetone when it cools to 20.0°C?
Physics
1 answer:
8_murik_8 [283]3 years ago
3 0

Answer:149.73 ml

Explanation:

Given

\beta \ of\ acetone=1.50\times 10^{-4} ^{\circ}C^{-1}

change in volume is given by

\Delta V=V_{final}-V_{initial}

\Delta V=\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]

V_{final}=\nu_{initial}+\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]

V_{final}=150+150\times 1.50\times 10^{-4}\left [ 20-32\right ]

V_{final}=149.73 ml

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Answer:

T = 1.1285 10⁻² day

Explanation:

For this exercise the forces in the premiere are internal, so the angular momentum is conserved

         L₀ = I₀ w₀

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         L₀ = L

         I₀ w₀ = I w

Angular velocity and period are related

         w₀ = 2π / T₀

         w = 2π  / T

         

The moment of inertia of a sphere is

       I₀ = 2/5 M R²

       I = 2/5 m r²

If we assume that the mass of the star does not change in the transformation

We substitute

         2/5 M R² 2π/T₀ = 2/5 M r² 2π/ T

          R² /T₀ = r² / T

          T = (r / R)² T₀

          T = (6.1 / 2.0 104) 37

          T = 1.1285 10⁻² day

5 0
3 years ago
How does water move from the surfaces of lakes, rivers, and the ocean directly back into the atmosphere?
Sergeeva-Olga [200]

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3 years ago
) A skier starts down a frictionless 32° slope. After a vertical drop of 25 m, the slope temporarily levels out and then slopes
EastWind [94]

Answer:

The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

Explanation:

Given that,

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Slope down = 20°

Height = 38 m

We need to calculate the skier’s speed on the two level stretches

Using formula of energy

P.E=K.E

mgh=\dfrac{1}{2}mv^2

v=\sqrt{2gh}

For first stretch,

Height = 25 m

Put the value into the formula

v=\sqrt{2\times9.8\times25}

v=22.13\ m/s

For second stretch,

Height = 38 m

Put the value into the formula

v=\sqrt{2\times9.8\times38}

v=27.29\ m/s

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5 0
4 years ago
1. A 700 kg satellite is in orbit 2.4 x 106 meters from the center of the Earth. What is the force of
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Answer:

4.8 \cdot 10^4 N

Explanation:

The force of gravity acting on the satellite is given by:

F=\frac{GMm}{r^2}

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m is the mass of the satellite

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Here we have

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Substituting into the equation, we find:

F=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(700)}{(2.4\cdot 10^6)^2}=4.8 \cdot 10^4 N

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3 0
3 years ago
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