Answer:
T = 1.1285 10⁻² day
Explanation:
For this exercise the forces in the premiere are internal, so the angular momentum is conserved
L₀ = I₀ w₀
L = I w
L₀ = L
I₀ w₀ = I w
Angular velocity and period are related
w₀ = 2π / T₀
w = 2π / T
The moment of inertia of a sphere is
I₀ = 2/5 M R²
I = 2/5 m r²
If we assume that the mass of the star does not change in the transformation
We substitute
2/5 M R² 2π/T₀ = 2/5 M r² 2π/ T
R² /T₀ = r² / T
T = (r / R)² T₀
T = (6.1 / 2.0 104) 37
T = 1.1285 10⁻² day
Answer:
B. Evaporation
Explanation:
Because I am absolutely positive
Please give Brainlyest
Answer:
The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.
Explanation:
Given that,
Slope down = 32°
Height = 25 m
Before leveling,
Slope down = 20°
Height = 38 m
We need to calculate the skier’s speed on the two level stretches
Using formula of energy



For first stretch,
Height = 25 m
Put the value into the formula


For second stretch,
Height = 38 m
Put the value into the formula


Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.
Answer:

Explanation:
The force of gravity acting on the satellite is given by:

where
G is the gravitational constant
is the Earth's mass
m is the mass of the satellite
r is the distance of the satellite from the Earth's centre
Here we have
m = 700 kg

Substituting into the equation, we find:

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>