Please, see the offered decision:
1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'.
2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5).
3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b:
3=0*(-3/5)+b ⇔ b=3.
4) finaly (k=-3/5; b=3):
Answer:
D
Step-by-step explanation:
The answer is point D(-2,1).
1. If the point D was moved down 2 units, then its coordinates became (-2,-1).
2. If point (-2,-1) was reflected over the x-axis, then its coordinates became (-2,1).
3. If the point (-2,1) was moved 4 units to the right, then its coordinates became (2,1).
4. If point (2,1) was reflected over y-axis, its coordinates became (-2,1).
They are already both positive numbers, so the absolute value of 2 is 2, and the absolute value of 1/3 is 1/3.