W=x
L=2x+17
Double everything since we need to lengths and two widths to find the perimeter
2x+17+2x+17+x+x = 76
Combine like terms
6x+34=76
Solve for x
First step is subtract 34 from both sides
6x=42
Next you divide both sides by 6 in order to get x by itself
X=7
Now you plug in 7 into the x’s in length and width
W=7 cm
L=31 cm
THE WIDTH IS 31 CM
Check:
7+7+31+31 = 76 cm
It equals 76 cm just like the problem said so therefore it is right.
No x does NOT equal 16. you would substitute x for 16 which gives you 16+12. That equals 28 not 30. The correct answer is x=18
Answer:
40% I think
Step-by-step explanation:
if it was on 20% and it's only gone up 20% it would now be at 40% but it still only has gone up 20%
<span> sin20 * sin40 * sin60 * sin80
since sin 60 = </span><span> √3/2
</span>√3/<span>2 (sin 20 * sin 40 * sin 80)
</span>√3/<span>2 (sin 20) [sin 40 * sin 80]
</span>
Using identity: <span>sin A sin B = (1/2) [ cos(A - B) - cos(A + B) ]
</span>√3/<span>2 (sin 20) (1 / 2) [cos 40 - cos 120]
</span>√3/4<span> (sin 20) [cos 40 + cos 60]
</span>
Since cos 60 = 1/2:
√3/4<span> (sin 20) [cos 40 + (1/2)]
</span>√3/4 (sin 20)(cos 40) + √3/8<span> (sin 20)
</span>
Using identity: <span> sin A cos B = 1/2 [ sin(A + B) + sin(A - B) ]
</span>√<span>3/4 (1 / 2) [sin 60 + sin (-20)] + </span>√3/8<span> (sin 20)
</span>
Since sin 60 = √3/<span>2
</span>√3/8 [√3/2 - sin 20] + √3/8 (sin 20)
3/16 - √3/8 sin 20 + √3/8<span> sin 20
</span>
Cancelling out the 2 terms:
3/16
Therefore, sin20 * sin40 * sin60 * <span>sin80 = 3/16</span>
Answer:
38 sq ft
Step-by-step explanation:
Add together the two triangles plus the rectangle area.
A(triangle1) = 1/2 bh = 1/2 4*4 = 8 sq ft
A(triangle2) = 1/2 bh = 1/2 4*3 = 6 sq ft
A(rectangle) = lw = 8*3 = 24 sq ft
A(total) = 8 + 6 + 24 = 38 sq ft
