Question

Two consecutive even numbers are such that five times the smaller number , subtracted from eight times the bigger gives 58. Find the two Numbers? show working​

Answer 1

Answer:

$14\text{ and }16$

Step-by-step explanation:

Let the smaller number be $x$. Since they are consecutive even numbers, the larger number can be represented by $x+2$.

Therefore, we have the following equation:

$8(x+2)-5x=58,\\8x+16-5x=58,\\3x=42,\\x=\boxed{14}$

Thus, the larger number is $x+2=\boxed{16}$