The values produced by the function
will not be any lower than -7, but may be that low when x=-3.
That is, the range is
... f(x) ≥ -7 . . . . matches the 1st selection
Answer:
Assuming you want the answer in slope-intercept form, it’s <u>y = -5x + 11</u>
Step-by-step explanation:
So we have to first use point-slope form, y - y1 = m (x - x1)
If we plug the numbers in we get...
y + 4 = -5 (x - 3) (take out parenthesis)
y + 4 = -5x + 15 (now subtract 4 from 15)
<u>y = -5x + 11</u>
I think this is right
The domain of the function can be represented using set-builder notation as follows: {x | x is a positive integer}. The range of the function can be represented using inequality notation as follows: 0 ≤ y ≤ 100.
<h3>What are the domain and range of the function?</h3>
The domain of the function includes all possible x values of a function, and the range includes all possible y values of the function.
Part A:
Hours Cost
1 10
3 30
11 100
20 100
Part B:
The domain of the function that represents the cost of renting a bicycle is the set of all possible values of the number of hours the bicycle is rented for. In this case, the domain is the set of all positive integers, because the bicycles must be returned the same day they are rented.
The range of the function is the set of all possible values of the cost of renting the bicycle. In this case, the range is the set of all non-negative numbers less than or equal to 100, because the maximum daily fee is $100.
Part C:
The domain of the function can be represented using set-builder notation as follows:
{x | x is a positive integer}
The range of the function can be represented using inequality notation as follows:
0 ≤ y ≤ 100
Learn more about the domain and the range here:
brainly.com/question/21027387
#SPJ1
(-2) + 6 + 1 = 1 + 6 + (-2)
-2 + 7 = 7 - 2
5 = 5
Answer:
We want to rewrite:
q^2 = a*(p^2 - b^2)/p
as a linear equation, in the form:
y = m*x + c
So we start with:
q^2 = a*(p^2 - b^2)/p
we can expand the left side to get:
q^2 = (a/p)*p^2 - (a/p)*b^2
q^2 = a*p - (a/p)*b^2
Now we can ust define:
a*p = c
Then we can replace that to get:
q^2 = -(a/p)*b^2 + c
now we can replace:
q^2 = y
b^2 = x
Replacing these, we get:
y = -(a/p)*x + c
finally, we can replace:
-(a/p) = m
then we got the equation:
y = m*x + c
where:
y = q^2
x = b^2
c = a*p
m = -(a/p)
