Answer:
One way to factor equation is to find the zeros. Its obvious that x=-1 is solution for this. So one factor is (x+1)
the next factor should include 2x at first (because we have 2x^2 in the equation which can not be made any other way)
Let's suppose the factor is (x+1)(2x+b)
Since we do not know what is b open the brackets 2x^2+bx+2x+b. If this is equal to 2x^2+5x+3 then b=3. We are left with (x+1)(2x+3)=2(x+1)(x+3/2)
Would go for other shorter solutions, but they require some deeper understanding like Horner's scheme,Fermat's Theorem or even deeper which I assume You will not understand)
Answer:
We just need to evaluate and get f(2i)=0, f(-2i)=0.
Step-by-step explanation:
Since
, then
, and we can apply this when we evaluate
for 2i and -2i.
First we have:

Which shows that 2i is a zero of f(x).
Then we have:

Which shows that -2i is a zero of f(x).
Answer:
The mean is the average of the numbers. It is easy to calculate: add up all the numbers, then divide by how many numbers there are.
Step-by-step explanation:
Answer:
80 + 18i
Step-by-step explanation:
i² = -1
x = i + 9
x² = (i + 9)²
Applying; (a + b)² = a² + 2ab + b² concept,
x² = i² + 18i + 81
We know that i² = -1
So x² = -1 + 18i + 81
x² = 81 - 1 + 18i = 80 + 18i