2 years ago

What are the coordinates of the image of the point (2, –6) under a dilation with a center of (0, 0) and a scale factor of 1/2.

1 answer:

7 0

The answer should be B.
(1, –3)

You might be interested in

Elanso [62]

yes. how'd you knowwww?

7 0

2 years ago

OLga [1]

Divide $0.75 by $36.75? Sorry if I'm wrong, mathematics isn't my best subject.

8 0

2 years ago

KIM [24]

Because then it would be easier to get an answer for a problem

6 0

2 years ago

nevsk [136]

Answer:

$x_2 \approx -1.769$

Step-by-step explanation:

Let $f(x)=x^3+x+7$

So $f'(x)=3x^2+1$

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

Let $x_1=-2$

We are going to find $x_2$

So we are evaluating $-2-\frac{f(-2)}{f'(-2)}$

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

$f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3$

$f'(-2)=3(-2)^2+1=3(4)+1=12+1=13$

$x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769$

5 0

2 years ago

mote1985 [20]

5-3(1/2x+2)=-7
-3(1/2x+2)=-7-5
(1/2x+2)=4
1/2x=2
x=4
just to give u an idea

4 0

2 years ago