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3 years ago

Shayla is a member of the kindness club. Their nent project is called "Making Kindness Grow and each member of the

Mathematics

1 answer:

IceJOKER [234]3 years ago

4 0

Even though it has not happened yet again

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Find the taxable income of a married couple with two children, who have a combined income of $75,000.

Dima020 [189]

Answer:

$47,200

Step-by-step explanation:

Given :

The total income of a married couple = $75,000.

Number of children = 2

Therefore to find the taxable income of a U.S. family is given by the following formula ---

taxable income = total income- exemption deduction - standard deduction

We know that exemption deduction for a U.S couple as fixed by the government is $15,600.

And the standard deduction for a U.S couple as fixed by the government is $12,200.

Thus in order to find the taxable income of the couple, use the formula

taxable income = total income- exemption deduction - standard deduction

= $75,000 - $15,600 - $12,200

= $47,200.

Thus the taxable income is $47,200.

8 0

4 years ago

What addition sentence helps you find 5 – 4?

sineoko [7]

Answer:

4 + x =5

Step-by-step explanation:

By adding a variable you can set up an addition sentence

6 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!

GarryVolchara [31]

Answer:

C) 3/8

Step-by-step explanation:

Find 1/8 + 1/4

1/8 + 1/4

= 1/8 + 2/8

= 3/8

7 0

2 years ago

The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

3 years ago

3,6,9,12 what operation was used to create the number pattern

Pachacha [2.7K]

Answer:

Step-by-step explanation:

u have an arithmetic sequence...ur adding 3 to every number to get to the next number

3 + 3 = 6

6 + 3 = 9

9 + 3 = 12

12 + 3 = 15

and so on...

4 0

3 years ago