<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1
Starting with the left: Note that cos²θ + </span><span>sin²θ = 1.
In the same way: </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore cos²3θ = 1 - <span>sin²3θ
</span> From the top: (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ
= 2/<span>sin² 3θ - 1; But 1/</span><span>sinθ = csc</span><span>θ, Similarly </span>1/sin3θ = csc3θ
= 2 *(1/sin<span>3θ)² - 1</span>
= 2csc²3θ - 1. Therefore LHS = RHS. QED.
Step-by-step explanation:
0 is right in the middle of all negative and all positive numbers.
0 is therefore larger than any negative number and smaller than any positive number.
and 0×n = 0, always, no matter what n is.
-0 = +0 = 0.
so, of course, only
4.1m > -16.4
is correct.
0 is not greater than 16.4.
0 is not smaller than -16.4.
Answer: y=-5x-8
Step-by-step explanation:
<h3>
Answer:</h3>
The transformation is a rotation.
<h3>
Step-by-step explanation:</h3>
The incorrect answers can be ruled out as follows:
- dilation would change the size, but not the directions of the lines
- reflection would change the DEF ordering from clockwise to counterclockwise
- translation would move the figure, but not change the directions of the lines
The image is the same size as the original. Each of the sides of the triangle is moved through the same angle. The transformation is a rotataion.
The center of rotation can be found as the point of intersection of the perpendicular bisectors of DD', EE' and FF'
