Step-by-step explanation:
i wish I could help but no idea
Answer:
A = 1100cm^2
Step by step Explanation:
given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.
If the width is equal to the length which I assume is true if the width is constant.
than x+30=2x, which means x = 30.
if this is true than 30(30)+200 = 1100cm^2
Answer:
Step-by-step explanation:
LHS = Sin² ∅ + Sin² ∅*tan² ∅
= Sin² ∅ [1 + tan² ∅ ] {Sec² ∅ - tan² ∅ = 1}
= Sin² ∅ *Sec² ∅
= Sin² ∅ * 
= Sin² ∅ /Cos² ∅
= tan² ∅ = RHS
L=length W=width
perimeter=2Lx2W
196=2L+2W
Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same
196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm
