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3 years ago

A picture is x+20 cm in width and 2x-10 cm in length. The frame is a

Mathematics

1 answer:

Jobisdone [24]3 years ago

8 0

Answer:

A = 1100cm^2

Step by step Explanation:

given the dimensions of width and length of the picture are x+20 by 2x-10 and the frame is a constant 5 cm wider from the edge of the picture to the frame, than the area of the frame is defined as (x+30)(2x)-(x+20)(2x-10) = 30x+200.

If the width is equal to the length which I assume is true if the width is constant.

than x+30=2x, which means x = 30.

if this is true than 30(30)+200 = 1100cm^2

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Y = mx + b

Yuki888 [10]

The last option, the y-intercept.

5 0

3 years ago

An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and

docker41 [41]

Answer:

the distance of the Bird (B) from the plane (P) is = 10779 ft

Step-by-step explanation:

From the given information:

a diagrammatic representation is attached below for better understanding and solution to the question.

From the diagram;

Let the Bird (B) be represent as A

The plane (P) be represented by B

The observer be represented by O

and the tower T be represented by C

we will see that:

$\overline {AB} \ \| \ \overline {OC}$

Also;

$\angle ABO = \angle BOC = 33^0$

AO = BC = 7000

Let consider the trigonometry of triangle BAO

tan θ = opposite/adjacent

tan 33° = 7000/x

0.6494 = 7000/x

x = 7000/0.6494

x = 10779.18

x = 10779 ft ( to the nearest whole number)

Thus; the distance of the Bird (B) from the plane (P) is = 10779 ft

7 0

3 years ago

Help please n thanks

garri49 [273]

Answer:

The answer I would choose is c

Hope this helped :)

5 0

2 years ago

A center for medical services reported that there were 295,000 appeals for hospitalization and other services. For this group, 4

pshichka [43]

Answer:

a) 0.0025 = 0.25% probability that none of the appeals will be successful.

b) 0.0207 = 2.07% probability that exactly one of the appeals will be successful.

c) 0.9768 = 97.68% probability that at least two of the appeals will be successful

Step-by-step explanation:

For each appeal, there are only two possible outcomes. Either it is succesful, or it is not. The probability of an appeal being succesful is independent of other appeals, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

45% of first-round appeals were successful.

This means that $p = 0.45$

Suppose 10 first-round appeals have just been received by a Medicare appeals office.

This means that $n = 10$

(a) Compute the probability that none of the appeals will be successful.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.45)^{0}.(0.55)^{10} = 0.0025$

0.0025 = 0.25% probability that none of the appeals will be successful.

(b) Compute the probability that exactly one of the appeals will be successful.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.45)^{1}.(0.55)^{9} = 0.0207$

0.0207 = 2.07% probability that exactly one of the appeals will be successful.

(c) What is the probability that at least two of the appeals will be successful

This is $P(X \geq 2)$

Either less than two appeals are succesful, or at least two are. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0025 + 0.0207 = 0.0232$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0232 = 0.9768$

0.9768 = 97.68% probability that at least two of the appeals will be successful

6 0

2 years ago

On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2). What is the length of Side RT

wolverine [178]

The distance between any two points can be found using the Pythagorean Theroem...

d^2=(x2-x1)^2+(y2-y1)^2 in this case

d^2=(2-2)^2+(1--6)^2

d^2=0+49

Since d>0

d=7 units

7 0

2 years ago

Read 2 more answers