Answer: Solving for f. Want to solve for x instead?
1 Remove parentheses.
f\times -2fx=3{x}^{2}-8x+7f×−2fx=3x
2
−8x+7
2 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
-{f}^{2}\times 2x=3{x}^{2}-8x+7−f
2
×2x=3x
2
−8x+7
3 Regroup terms.
-2{f}^{2}x=3{x}^{2}-8x+7−2f
2
x=3x
2
−8x+7
4 Divide both sides by -2−2.
{f}^{2}x=-\frac{3{x}^{2}-8x+7}{2}f
2
x=−
2
3x
2
−8x+7
5 Divide both sides by xx.
{f}^{2}=-\frac{\frac{3{x}^{2}-8x+7}{2}}{x}f
2
=−
x
2
3x
2
−8x+7
6 Simplify \frac{\frac{3{x}^{2}-8x+7}{2}}{x}
x
2
3x
2
−8x+7
to \frac{3{x}^{2}-8x+7}{2x}
2x
3x
2
−8x+7
.
{f}^{2}=-\frac{3{x}^{2}-8x+7}{2x}f
2
=−
2x
3x
2
−8x+7
7 Take the square root of both sides.
f=\pm \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}f=±√
−
2x
3x
2
−8x+7
8 Simplify \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}√
−
2x
3x
2
−8x+7
to \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imath√
2x
3x
2
−8x+7
ı.
f=\pm \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imathf=±√
2x
3x
2
−8x+7
ı
9 Regroup terms.
f=\pm \imath \sqrt{\frac{3{x}^{2}-8x+7}{2x}}f=±ı√
2x
3x
2
−8x+7
Done- :)
f=±ı√ 2x 3x 2 −8x+7
Step-by-step explanation
Answer:
Step-by-step explanations
Clay 1.5 0.12 30
Silty Clay 1.9 0.18 40
Clay Loam 2.4 0.25 40
Silty Clay Loam 2.4 0.25 50
Sandy Clay Loam 1.8 0.20 50
Sandy Clay 1.9 0.12 50
Silt 2.0 0.40 50
Silty Loam 2.4 0.43 50
Loam 2.0 0.54 50
Sandy Loam 1.4 0.75 50
Loamy Sand 0.8 0.88 50
Fine Sand 0.7 1.25 60
The only possible one is 1/8 and the answer would be B. 0.125
Answer:
The correct answer is (d) 36 units.
Step-by-step explanation:
Just took the test on edge :)
Answer:
Step-by-step explanation: