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san4es73 [151]
3 years ago
7

D(1)=3 d(n) = d(n-1) - 14 what is the third term in the sequence

Mathematics
1 answer:
Aliun [14]3 years ago
6 0
2nd term  =  3 - 14 = -11
3rd tern = -11-14 = -25 answer
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Find f (-2) f(x)= 3x^2 - 8x + 7
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Answer: Solving for f. Want to solve for x instead?

1 Remove parentheses.

f\times -2fx=3{x}^{2}-8x+7f×−2fx=3x

​2

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2 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

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3 Regroup terms.

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6 Simplify  \frac{\frac{3{x}^{2}-8x+7}{2}}{x}

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​​

​​   to  \frac{3{x}^{2}-8x+7}{2x}

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​​ .

{f}^{2}=-\frac{3{x}^{2}-8x+7}{2x}f

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7 Take the square root of both sides.

f=\pm \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}f=±√

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​

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8 Simplify  \sqrt{-\frac{3{x}^{2}-8x+7}{2x}}√

​−

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​

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​​

​

​​   to  \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imath√

​

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​​

​

​​ ı.

f=\pm \sqrt{\frac{3{x}^{2}-8x+7}{2x}}\imathf=±√

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​

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​​

​

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f=\pm \imath \sqrt{\frac{3{x}^{2}-8x+7}{2x}}f=±ı√

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Done- :)

f=±ı√ ​2x 3x 2 −8x+7

​​

​

​​

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