Complete the square fr x and y's sepreatly to get into form
(x-h)²+(y-k)²=r²
the center is (h,k) and radius is r
so
group x's and y's seperatly
(4x²-10x)+(4y²+24y)+133/4=0
undistribute leading confident from each
4(x²-2.5x)+4(y²+6y)+133/4=0
take 1/2 of each linear confident and square it and add negative and positive inside the parenthasees
-2.5/2=-1.25 (-1.25)²=1.5625
6/2=3, 3²=9
4(x²-2.5x+1.5625-1.5625)+4(y²+6y+9-9)+133/4=0
factor perfect squares
4((x-1.25)²-1.5625)+4((y+3)²-9)+133/4=0
expand
4(x-1.25)²-6.25+4(y+3)²-36+133/4=0
4(x-1.25)²+4(y+3)²-9=0
add 9 to both sides
4(x-1.25)²+4(y+3)²=9
divide both sides by 4
(x-1.25)²+(y+3)²=9/4
(x-1.25)²+(y+3)²=(3/2)²
the center is (1.25,-3) and the radius is 1.5
Answer:
love his music... absolutely insane
Step-by-step explanation:
my favorite song is paid my dues my nf. One reason why I like it is because I can relate closely to it. it also gives a really chill but dark vibe. I think this song is supposed to be about how the rapper, nf just wants a regular life with regular friends.
Answer:
Yes they are directly proportional quantities.
Step-by-step explanation:
We find the area of a square by;
A = length squared or (L)² , where 'L' stands for length and 'A' stands for area.
So Area = L²
Assume the length is a units and increase the length by 2 units
The initial area before increasing the length is a²
After increasing the length, the area becomes: (a + 2)² = a² + 4a + 4
Now we subtract the initial area from the final area and get;
(a² + 4a + 4) - a² = 4a + 4
So the new area increases by 4a + 4 units.
Hence, the area increases as the length increases implying that the area of a square is directly proportional to its length.
We denote this proportionality as;
A ∝ L
Answer: 44 m
Step-by-step explanation:
Given
The area of the trapezium is 
Distance between parallel sides 
One of the parallel sides is 
Suppose the other parallel side is 
The area of the trapezium is
![A=\dfrac{1}{2}\times [\text{Sum of parallel sides}]\times h](https://tex.z-dn.net/?f=A%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%5B%5Ctext%7BSum%20of%20parallel%20sides%7D%5D%5Ctimes%20h)
Put values
![\Rightarrow 480=\dfrac{1}{2}\times [20+x]\times 15\\\\\Rightarrow 480\times 2=300+15x\\\Rightarrow 960-300=15x\\\Rightarrow x=44\ m](https://tex.z-dn.net/?f=%5CRightarrow%20480%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20%5B20%2Bx%5D%5Ctimes%2015%5C%5C%5C%5C%5CRightarrow%20480%5Ctimes%202%3D300%2B15x%5C%5C%5CRightarrow%20960-300%3D15x%5C%5C%5CRightarrow%20x%3D44%5C%20m)
