Im not good in math and this is my first question, my best guess is D
I will investigate tommorow this problem a little bit more... <3
Answer: There are two solutions and they are
theta = 135
theta = 225
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Explanation:
Recall that x = cos(theta). Since the given cosine value is negative, this indicates x < 0. Theta is somewhere to the left of the y axis, placing it in quadrant 2 or quadrant 3.
It turns out there are two solutions, with one solution per quadrant mentioned above. Use the unit circle to find that the two solutions are:
theta = 135
theta = 225
You're looking for points on the unit circle that have x coordinate equal to x = -sqrt(2)/2. Those two points correspond to the angles of 135 and 225, which are in quadrants 2 and 3 respectively.
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I recommend using your calculator to note that
-sqrt(2)/2 = -0.70710678
cos(135) = -0.70710678
cos(225) = -0.70710678
The decimal values are approximate. Make sure your calculator is in degree mode. Because those three results are the same decimal approximation, this indicates that cos(135) = cos(225) = -sqrt(2)/2.
9514 1404 393
Answer:
195 ft
Step-by-step explanation:
The relationship between the horizontal distance, angle, and vertical height is given by ...
Tan = Opposite/Adjacent
Referring to the attached diagram, we have ...
tan(16°) = BT/MB
tan(25°) = BK/MB
Solving for BT and BK, we can describe their difference as ...
BT = MB·tan(16°)
BK = MB·tan(25°)
BK -BT = 35 = MB(tan(25°) -tan(16°))
Dividing by the coefficient of MB gives ...
MB = 35/(tan(25°) -tan(16°)) = 35/0.179562
MB = 195 . . . feet
Marcos is standing 195 feet from the base of the tree.
Answer:
y+2= -1/5(x+1)
Step-by-step explanation:
if lines are perpendicular their slopes are negative reciprocal
y=mx+b where m is the slope
y=5x-10 has the slope 5 so a perpendicular line will have slope -1/5
equation point slope form
(y-y1) = m(x-x1) where m is slope, and (x1,y1) any point that belongs to the line
y+2= -1/5(x+1)
