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Lyrx [107]
2 years ago
7

Find the probability that a randomly selected multiple birth for women​ 15-54 years old involved a mother who was at least 40 ye

ars old. ​P(at least ​40
Mathematics
2 answers:
Nikolay [14]2 years ago
6 0

Answer:3/8

Step-by-step explanation:

Total number of women with ages from 15 to 54years (15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54)= 40

Total number of women with age 40 years and above = 15

Probability of picking a mother of age greater than 40 = 15/40 which is equal to 3/8.

serious [3.7K]2 years ago
4 0

Age Number of Multiple Births

15–19 100

20–24 467

25–29 1620

30–34 2262

35–39 1545

40–44 328

45–54 105

---------------------------

Total. 6427

-----------------------------

Answer:

Probability of selecting a mother who is at least 40 years old is 0.067.

That means there are 6.7% of the the total mothers who are at least 40 years old.

Step-by-step explanation:

The question is looking for probability of a mother at least 40 years.

It means 40 years and above.

From the table, the number of mothers who fall into this category = 328 +105 = 433

So, the probability would be = 433/6427 = 0.067

Therefore, converting to percentage, we have 6.7%

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Find the missing number to make these fractions equal.<br><br> 3/4 = ?/8
babymother [125]

The answer is 6, reaosn is because 6/8 is not simplified, so if we divide both sides by 2 (the numerator and the denominator), we can get a simplified fraction, which is 3/4. Steps: 6/8, 6 divided by 2/8 divided by 2, 3/4.

Hope this helped!

Nate

7 0
3 years ago
Which of the following statements about the sampling distribution of the sample mean, x-bar, is not true? A. The sampling distri
Elenna [48]

Answer: E. All of the above statements are true

Step-by-step explanation:

The mean of sampling distribution of the mean is simply the population mean from which scores were being sampled. This implies that when population has a mean μ, it follows that mean of sampling distribution of mean will also be μ.

It should also be noted that the distribution's shape is symmetric and normal and there are no outliers from its overall pattern.

The statements about the sampling distribution of the sample mean, x-bar that are true include:

• The sampling distribution is normal regardless of the shape of the population distribution, as long as the sample size, n, is large enough.

• The sampling distribution is normal regardless of the sample size, as long as the population distribution is normal. • The sampling distribution's mean is the same as the population mean.

• The sampling distribution's standard deviation is smaller than the population standard deviation.

Therefore, option E is the correct answer as all the options are true.

7 0
3 years ago
State the domain and range for the following relation. Then determine whether the relation represents a function
ankoles [38]

Answer:

  • domain = (Rosa,Alia,Alice,Marie)
  • Range = (Alan,Hank,Ben)
  • Is a function

Step-by-step explanation:

Because each member in the domain has only one element on the co domain

7 0
2 years ago
Round 1627187 to the nearest ten?
Eduardwww [97]

Answer:

1627190

Step-by-step explanation:

(see attached for reference)

Given the number 1627187, we can see that the number in the tens place is the number 8.  

How we round this depends on the number immediately to the right of this number. (i.e the digit in the ones place)

Case 1: If the digit in the ones place is less less than 5, then the number in the tens place remains the same and replace all the digits to its right with zeros

Case 2: If the digit in the ones places is 5 or greater, then we increase the digit in the tens place and replace all the digits to its right with zeros.

In our case, the digit in the ones places is 7, this greater than 5, hence according to Case 2 above, we increase the digit in the tens place by one (from 8 to 9) and replace all the digits to its right by zeros giving us:

1627190

7 0
3 years ago
Read 2 more answers
10. A company finds that 45% of first-time visitors to its website do not buy any of its products. If there are 75 first-time vi
vekshin1

Using the binomial distribution, it is found that the probability that exactly 36 of them buy a product is of 0.044.

For each first-time visitor, there are only two possible outcomes, either they buy a product, or they do not. The probability of a first-time visitor buying a product is independent of any other first-time visitor, hence the binomial distribution is used to solve this question.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 45% of first-time visitors to its website do not buy any of its products, hence 55% buy, that is, p = 0.55.
  • There are 75 first-time visitors on a given day, hence n = 75.

The probability that exactly 36 of them buy a product is P(X = 36), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 36) = C_{75,36}.(0.55)^{36}.(0.45)^{39} = 0.044

More can be learned about the binomial distribution at brainly.com/question/24863377

8 0
2 years ago
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