Question

6+2i

Answer 1

$\frac{6+2i}{3+3i}=\frac{6+2i}{3+3i}\times\frac{3-3i}{3-3i}$
$\frac{6+2i}{3+3i}=\frac{18-18i+6i-6i^{2}}{9-9i+9i-9i^{2}}$
$\frac{6+2i}{3+3i}=\frac{18-12i+6}{9+9}$
$\frac{6+2i}{3+3i}=\frac{24-12i}{18}$
$\frac{6+2i}{3+3i}=\frac{12(2-i)}{18}$
$\frac{6+2i}{3+3i}=\frac{2(2-i)}{3}$
$\frac{6+2i}{3+3i}=\frac{2}{3}(2-i)$
$\frac{6+2i}{3+3i}=\frac{4}{3}-\frac{2i}{3}$