All categories

2 years ago

I need help with this

Mathematics

2 answers:

luda_lava [24]2 years ago

8 0

The answer would be c. 3 (x+5) because you would add x and 5 to get the base of the rectangle then multiply it by the hight (3)

Snowcat [4.5K]2 years ago

7 0

Answer:

3 (x+5)

Step-by-step explanation:

You might be interested in

Solve for x: 2x - 2 > 4x + 6

laiz [17]

Isolate the x. Subtract 4x from both sides, and add 2 to both sides

2x (-4x) - 2 (+2) > 4x (-4x) + 6 (+2)

2x - 4x > 6 + 2

Simplify. Combine like terms

-2x > 8

Isolate the x. Divide -2 from both sides. Note that you are <em>dividing a negative number</em>. When doing so, flip the sign.

-2x/-2 > 8/-2

x > 8/-2

x < -4

x < -4, or (1) is your answer

hope this helps

7 0

3 years ago

Need help STAT 100 POINTS

n200080 [17]

Answer:

it would be 59.5

6 0

2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

6 0

3 years ago

Read 2 more answers

Given the system of linear equations:

Vanyuwa [196]

Answer:

Step-by-step explanation:

hello :

Part A : x+6y =6 means : 6y = - x+6

so : y = (-1/6)x+1 an equation for the line (D)

y = (1/3)x -2 is the line (D')

PartB : solution of the system : y = (-1/6)x+1 ....(1) color red

y = (1/3)x -2 ....(2) color bleu

is the intersection point : (6 ; 0)

PartC : Algebraically by (1) and (2) : (-1/6)x+1 = (1/3)x -2

(-1/6)x - (1/3)x = -2-1

(-x-2x)/6= -3

-3x = -18

so : x = 6 put this value in (1) or (2) : y = (-1/6)(6)+1 =0 the solution is : (6 ;0)

3 0

3 years ago

Write an equation for the line below

olga_2 [115]

Answer:

y = 4/5x

Step-by-step explanation:

Two points on the graph is (-5, -4) and (0, 0)

Slope formula is [ y2-y1/x2-x1 ]

0-(-4)/0-(-5)

4/5

The y-intercept is non existent since its 0.

y = 4/5x

Best of Luck!

3 0

3 years ago