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OverLord2011 [107]
3 years ago
5

I need help with this

Mathematics
2 answers:
luda_lava [24]3 years ago
8 0
The answer would be c. 3 (x+5) because you would add x and 5 to get the base of the rectangle then multiply it by the hight (3)
Snowcat [4.5K]3 years ago
7 0

Answer:

3 (x+5)

Step-by-step explanation:

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Apply the distributive property to create an equivalent expression. ( 1 − 2 g + 4 h ) ⋅ 5 =
mina [271]

Answer:

{(1-2g) + 4h] x 5 =

Step-by-step explanation:

8 0
3 years ago
I will mark either the best or the first answer brainliest.
posledela

Answer:

11.x=16 12.x=37

Step-by-step explanation:

11.

20^2-12^2=x^2

256=x^2

x=√256

x=16

12.

13^2-5^2=y^2

144=y^2

y=12

/

y^2+35^2=x^2

12^2+35^2=x^2

1369=x^2

x=37

5 0
3 years ago
Read 2 more answers
Hi could someone tell me how to solve this, you don’t even have to tell me the answer I’m just confused on this math and need he
BabaBlast [244]

Answer:

132 ft

Step-by-step explanation:

The radius is 21 ft

We want to find the circumference

C = 2 * pi *r

Letting pi = 22/7

C = 2 * 22/7 * 21

C = 132 ft

8 0
3 years ago
Read 2 more answers
Elena’s bus runs every 20 minutes. If she arrives at her bus stop at a random time, what is the probability that she will have t
Bond [772]
We try to represent the data in segments from 0 to 20.
<span>The length of the line segment along the number line from 0 to 5 is 5 - 0 = 5 units. The length of the line segment along the number line from 20 to 5 is 20 - 5 = 15 units. If you were to randomly throw a dart on this number line, then the probability of landing in the shaded region is 15/20 = 3/4 or 75%</span>
6 0
3 years ago
Read 2 more answers
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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