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Semenov [28]
3 years ago
11

If a small car can hold 50 liters of gas. How many milliliters is that?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
8 0
There are 50,000 milliliter in 50 liters of gas
m_a_m_a [10]3 years ago
7 0
For every liter of gas there is 1,000 milliliters. If you multiply 50 liters by 1,000 milliliters you will get 50,000mls. 
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ESTIMATE FOR 85.1 divided by 23
Korvikt [17]

Answer:

3.7 is your answer or 4.0 or 4


Step-by-step explanation:


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3 years ago
Quadrilateral ABCD​ is inscribed in this circle.
Svetllana [295]

Answer:

132°

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle,

So, it is a cyclic quadrilateral.

Opposite angles of a cyclic quadrilateral are supplementary.

\implies \: x \degree + (3x - 12) \degree = 180 \degree \\  \\ \implies \: (4x - 12) \degree = 180 \degree \\  \\  \implies \: 4x - 12  = 180  \\  \\ \implies \: 4x   = 180  + 12 \\  \\ \implies \: 4x   = 192 \\  \\ \implies \: x   =  \frac{192}{4}  \\  \\ \implies \: x   = 48\\\\

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5 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acce
g100num [7]

Here is the correct format for the question

At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box. By the Mean Value Theorem, there is a number c such that 0 < c < \Box  with v'(c) = \Box. Since v'(t)  is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.

Answer:

Step-by-step explanation:

From the information given :

At  2:00 PM ;

a car's speedometer v(0) = 30 mi/h

At 2:15 PM;

a car's speedometer v(1/4) = 50 mi/h

Given that:

v(f) should be the velocity of the car t hours after 2:00 PM

Then \dfrac{v(1/4)-v(0)}{1/4 -0} = \Box will be:

= \dfrac{50-30}{1/4 -0}

= \dfrac{20}{1/4 }

= 20 × 4/1

= 80 mi/h²

By the Mean value theorem; there is a number c such that :

\mathbf{0 < c< \dfrac{1}{4}}     with \mathbf{v'(c) = \dfrac{v(1/4)-v(0)}{1/4 -0}} \mathbf{ = 80 \ mi/h^2}

6 0
3 years ago
a fruit basket contains oranges and grapefruits. one third of the oranges and one fourrth of the grapefruits were spoiled. you t
nignag [31]
If 1/3 of the oranges were spoiled and you threw away 4 oranges, there would be a total of 12 oranges.
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7 x 4 = 28
Add the total amount of oranges to the total amount of grapefruits and you get how many pieces of fruit were in the basket.
12 + 28 = 40
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4 years ago
Sally is planning the school picnic and needs to decide what food vendor to
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Answer:0.03

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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