Answer:
3.7 is your answer or 4.0 or 4
Step-by-step explanation:
Answer:
132°
Step-by-step explanation:
Quadrilateral ABCD is inscribed in a circle,
So, it is a cyclic quadrilateral.
Opposite angles of a cyclic quadrilateral are supplementary.

(3x-12)° = (3*48 - 12)° = (144 - 12)° = 132°

Here is the correct format for the question
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:15 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:15 the acceleration is exactly 80 mi/h².Let v(f) be the velocity of the car t hours after 2:00 PM.Then
. By the Mean Value Theorem, there is a number c such that 0 < c <
with v'(c) =
. Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 80 mi/h^2.
Answer:
Step-by-step explanation:
From the information given :
At 2:00 PM ;
a car's speedometer v(0) = 30 mi/h
At 2:15 PM;
a car's speedometer v(1/4) = 50 mi/h
Given that:
v(f) should be the velocity of the car t hours after 2:00 PM
Then
will be:


= 20 × 4/1
= 80 mi/h²
By the Mean value theorem; there is a number c such that :
with 
If 1/3 of the oranges were spoiled and you threw away 4 oranges, there would be a total of 12 oranges.
4 x 3 = 12
If 1/4 of the grapefruits were spoiled and you threw away 7 grapefruits, there would be a total of 28 grapefruits.
7 x 4 = 28
Add the total amount of oranges to the total amount of grapefruits and you get how many pieces of fruit were in the basket.
12 + 28 = 40
Answer:0.03
Step-by-step explanation: