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elixir [45]
3 years ago
6

a clothing store offers very often various promotions to attract customers but wants to maintain the same amount of profit to do

this the store mark up prices above retail and then advertises a deal that results in a markdown equivalent to a retail price. the retail prices of a necktie is $59.99 the store offers a buy 2 get 1 free deal on neckties. what is the new retail price during this promotion ? what is the markup ? what is the markup percent on a tie during the promotion?
Mathematics
1 answer:
Fynjy0 [20]3 years ago
7 0
The answer is 120.Just by adding 6+6=12
you know the answer
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How do I find the percentage of filled seats verus non filled seats for a class
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Answer:

since i dont have data this is the best i can do

Step-by-step explanation:

non-filled seats diveded by total number of seats, everything multilped by 100 gives you percentage of non-filled seats.

Filled seats diveded by total number of seats, everything multilped by 100 gives you percentage of filled seats.

total should add up to 100

5 0
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For for every ten sheets of stickers you buy at a craft store the total cost increases $20.50
Len [333]

The equation which relates the change in price per sticker purchased is y = 2.05x

  • The number of stickers purchased = 10

  • Price change = $20.50

The change in price per sticker purchased can be expressed as :

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  • Change in price per sticker = $20.50 / 10

  • Change in price per sticker purchased = 2.05

Therefore, the required equation which related y and x is :

y = 2.05x

Learn more :brainly.com/question/13218948

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5 0
3 years ago
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Javier bought a 20-pound bag of dog food for his Great Dane, Tank. After 7 days, all the dog food was gone.
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Step-by-step explanation:

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7 0
3 years ago
Prove that sinxtanx=1/cosx - cosx
maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}

Taking the RHS, note

\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}

Remember that

\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)

Therefore,

\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}

Once

\dfrac{\sin(x)}{\cos(x)} = \tan(x)

Then,

\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)

Hence, it is proved

5 0
3 years ago
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