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marta [7]
3 years ago
15

The intersection of roads M and N creates a 41.4 degree angle. What are the complimentary and supplementary angles of this inter

section?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0
Supplementary angles are two angles which sum up to 180 degrees while complementary angled are those the sum is 90 degrees. Therefore, the complementary of 41.4 is 90-41.4 = 48.6 and the supplement would be 180-41.4= 138.6.
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I need help with this math worksheet.im not smart at all.
garik1379 [7]

Answer:

1) 11.581

2) 10.78

3) 14.8

4) 3.5

5) 16.28

6) .64

7) 23.3

8) 1.24

9) 6.53

10) 1.59

11) 8.79

12) 27.7919

Step-by-step explanation:

Ur smarter than u think. ^_^

7 0
3 years ago
Read 2 more answers
The population of bacteria doubles every 6 hours. By how much will it grow in three days. Write the equation
ch4aika [34]

Answer:

Step-by-step explanation:

let x be the population

so we have ,

2x= 6h

?= 3 days or 3×24h

by cross multiplication we have

2x× 72h= 6h×?

?= 2x×72/6 = 24x

So, in three days the bacteria will b 24 times current population.

8 0
3 years ago
I need help with completing the reasons for the proof. The first 3 statments are given. ​
Oxana [17]

Answer:Two-column, paragraph, and flowchart proofs are three of the most common geometric proofs. They each offer different ways of organizing reasons and statements so that each proof can be easily explained.

Step-by-step explanation:

4 0
3 years ago
Find the area of a triangle with a =33, b =51, and c =42.
PolarNik [594]

Answer:

d. 690.1 units²

Step-by-step explanation:

1. You can use the Heron's formula to calculate the area of the triangle, which is:

K=\sqrt{s(s-a)(s-b)(s-c)}

Where:

s=\frac{a+b+c}{2}

2. Calculate s:

s=\frac{33+51+42}{2}\\s=63

3. Substitute values into the formula shown above and calculate the area, as following:

K=\sqrt{63(63-33)(63-51)(63-42)}\\K=690.1units^{2}

4. Therefore, the area is 690.1 units².

4 0
3 years ago
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kari74 [83]
The river flows at 2 miles per hour. This is the speed of the current, or the speed at which the water itself is moving.

The mass of the particles moving in river is proportional to the sixth power of 2, or 2^6 = 64 miles per hour. So, if x is the mass of the particle, then the speed is modeled by an inverse relationship x * 2^6 = k, for some constant k. 

For particles that are 15 times the usual mass, the speed of the river itself must increase for the particles to travel at the same speed as before. The mass of the particles is still proportional to the sixth power of the speed of the river, but the speed of the river can no longer be 2 miles per hour. It is some speed y, which we are solving for.

So, the key here is proportional. We can set up two proportions and cross multiply.

\dfrac{x}{2^6} =  \dfrac{15x}{y^6}  \\ (x)(y^6)=(2^6)(15x)

Cancelling our x's (because we don't need to solve for them), we have

y^6 = 15(2^6) = 15(64)=960

To solve for y, we must take the sixth root of both sides, or raise both sides to the one-sixth power.

\sqrt[6]{y^6} =  \sqrt[6]{960}

Using a calculator, we see that \sqrt[6]{960} = 3.14 \ miles \ per \ hour.
6 0
3 years ago
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