Answer:
Step-by-step explanation:
y = ax² + bx + c
~~~~~~~
(4, - 2), (8, 6), (2, 0)
a(4²) + b(4) + c = - 2
a(8²) + b(8) + c = 6
a(2²) + b(2) + c = 0
16a + 4b + c = - 2 .............. <em>(1)</em>
64a + 8b + c = 6 ............... <em>(2)</em>
4a + 2b + c = 0 ................. <em>(3)</em>
a = 0.5 ; b = - 4 ; c = 6
<em>y = 0.5x² - 4x + 6</em>
Part A: (0, 6), (6, 0)
Part B: (0,6)
Part C: (6, 0)
Part D: [ 4, ∞ )
Option D:
all real numbers
Solution:
<u>Definition of domain:</u>
The domain of the function is the set of all possible
x-values (independent variable).
<u>Definition of range:</u>
The range of a function is the set of all possible resulting values
of y-values (dependent variable).
i.e The range of a function is the resulting y-values we get after substituting all the possible x-values.
Given function:
Domain of y: (0, ∞) (or) {x | x > 0}
Range of y: (–∞, ∞) (or) {y | y > R}
i.e all real numbers
Option D is the correct answer.
Hence the range of y is all real numbers.