Answer: Norm Alpina did better with z-score 0.79
Step-by-step explanation:
Z score formula = (raw score - mean) / standard deviation
For Jack Hartig,
score = 4; mean = 2.9; standard deviation = 2.1
Hence, Z score = (4 - 2.9) /2.1
= 1.1/2.1
= 0.52
For Norm Alpina,
score = 8; mean = 6.5; standard deviation = 1.9
Hence, Z score = (8 - 6.5) /1.9
= 1.5/1.9
= 0.79
Relatively, Norm Alpina did better for having Z score 0.79
Answer:
Pierre has enough boards and nails to make 9 tables and 5 chairs.
Step-by-step explanation:
13T+8C ≤ 220
Let us substitute 9 for T and 5 for C and check.
13(9) + 8(5) = 117 + 40
= 157 < 220
So, 220 wooden boards are sufficient to make 9 tables and 5 chairs.
48T+37C ≤ 760
Substitute 9 for T and 5 for C.
48(9)+37(5) = 432 + 185
= 617 < 760
So, 760 nails are sufficient to make 9 tables and 5 chairs.
Hence, Pierre has enough boards and nails to make 9 tables and 5 chairs.
Answer:
I'd use a Non-probability Sampling Method.
Explanation:
The question is already laced with criteria - Heights of Buildings in New York.
This means that there are certain buildings that won't fit in the sample. In a non-probability sample, objects or subjects are elected based on specified criteria that are not random. This means that not all objects/subject have a c<em>hance</em> of being included in the sample.
It is assumed that the question/assignment centers around high rise buildings.
Therefore, one storey buildings and bungalows that are within and outside New York will not be included in the sample.
Under the Non-Probability Sampling Method, it is essential to note that there are other subgroupings of sampling techniques. They are:
- Convenience Sample
- Voluntary Sample
- Purposive Sample
- Snowball Sample
Cheers!
1/2 over -2/5 + (-1/4)
10/20 over -8/20 + (-5/20)
1 5/20 + (-5/20)
1
The answer is 1
