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3 years ago

13

How do you write 143% as a decimal

2 answers:

umka2103 [35]3 years ago

7 0

Answer:

1.43

Step-by-step explanation:

1.43 or 1 43/100 turned into a percent is 143%

Naddik [55]3 years ago

3 0

Answer:

1.43 because 1 = 100 percent and the 43 is your 43 remaining

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I wasn't in school today can someone explain how to do this

Pachacha [2.7K]

You have to multiply 7 3/4 to 9.

First, turn 7 3/4 to an improper fraction which is 31/4.
Next, you multiply 31/4 to 9/1(same thing as 9) across from each other.
Then, you get the answer 279/4(31 x 9 = 279 ;4 x 1 = 4; 279/4).
Last divide 279 to 4 and get 67.75( .75 = 3/4 ; 69 3/4).

7 0

3 years ago

What’s is part A?? .....

bixtya [17]

Answer:

A. 3

B. 4

C. 1

D. 2

Step-by-step explanation:

Consider all equations:

A. $y=x^2 -6x+8$

This is the equation of parabola with vertex at point

$x_v=\dfrac{-b}{2a}=\dfrac{-(-6)}{2\cdot 1}=3\\ \\y_v=3^2-6\cdot 3+8=9-18+8=-1$

The y-intercept is at point

$x=0\\ \\y=0^2-6\cdot 0+8=8$

Since

$x^2 -6x+8=x^2-4x-2x+8=x(x-4)-2(x-4)=(x-2)(x-4)$ ,

the x-intercepts are at points (2,0) and (4,0)

The leading coefficient is 1 > 0, then the parabola opens upwards.

Hence, the graph of this parabola is 3.

B. $y=(x-6)(x+8)$

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is 1 > 0, then the parabola opens upwards.

The only possible choice is parabola 4.

C. $y=(x-6)^2+8$

This parabola has the vertex at point (6,8), opens upwards, therefore does not intersect the x-axis.

The graph of this parabola is 1.

D. $y=-(x+8)(x-6)$

This parabola has two x-intercepts at points (6,0) and (-8,0).

The leading coefficient is -1 > 0, then the parabola opens downwards.

The only possible choice is parabola 2.

4 0

3 years ago

Read 2 more answers

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe

timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

$EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5$

So,

$EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1$

And

$GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)$

Now

$FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\ ..... (2)$

Solving (1) and (2)

b = - 2 ,

$a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6$

3 0

3 years ago

Please answer this I’ll make you Brainly

sergejj [24]

Answer:

y = -63

Step-by-step explanation:

y - 15 = -78

Add 15 on both sides to get y alone:

y - 15 + 15 = -78 + 15

y = -63

7 0

3 years ago

Read 2 more answers

Jehane had a mark of 39 on a test.<br> This mark was 60%.<br> What was the total possible mark?

cricket20 [7]

the mark was 39/65, dividing the answer you get 0.6 which is 60%

3 0

3 years ago