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jenyasd209 [6]
4 years ago
14

Someone draws a card at random out of a deck, replaces it, and then draws another card at random. What is the probability that t

he first card is the ace of clubs and the second card is a club (any club).
I don't need an explanation, just the answer
Mathematics
2 answers:
vaieri [72.5K]4 years ago
8 0
1 ace of clubs - 1/52
Clubs - 1/4

1/4*1/52 = 1/208

The answer is 1/208
Lyrx [107]4 years ago
7 0
1/208 if there's no joker
13/2916 if there's joker
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The sales tax rate is 4.3064.306​% for the city and 44​% for the state. Find the total amount paid for 33 boxes of chocolates at
svp [43]

Answer:

The Total amount of of 33 boxes of chocolates including taxes is $838.358

Step-by-step explanation:

Given as :

The sales tax rate for city = 4.306%

The sales tax rate for the state = 44%

Total number of boxes = 33

The price of each chocolates = $17.13

So , The price of 33 boxes of chocolates = $17.13 × 33

I.e The price of 33 boxes of chocolates = $565.29

Now total tax including state and city =  4.306% + 44% = 48.306 %

So, The tax amount paid for 33 boxes of chocolates = 48.306 % of $565.29

∴    The tax amount paid for 33 boxes of chocolates = 48.306 % × $565.29

                                                                       = 0.48306× $565.29

                                                                       = $273.068

∴ The Total amount of of 33 boxes of chocolates including taxes = $565.29 +  $273.068 = $838.358

Hence The Total amount of of 33 boxes of chocolates including taxes is $838.358 . Answer

4 0
3 years ago
When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con
marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force F applied to an object with mass m is directly proportional to its acceleration a:

F=ma (1)

If we isolate a:

a=\frac{F}{m} (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

m_{1}=4 kg

a_{1}=5 m/s^{2}

F=m_{1}a_{1} (3)

F=(4 kg)(5 m/s^{2) (4)

F=20 N (5)

If we apply this same force calulated in (4) in another object with an acceleration of a_{2}=2 m/s^{2}, its mass m_{2} will be:

F=m_{2}a_{2} (6)

20 N=m_{2}2 m/s^{2} (7)

Finding  m_{2}:

m_{2}=10 kg This is the mass of the object

4 0
3 years ago
Math help please help me with this page
White raven [17]
Please, post just one problem at a time, or (if you post more than one), indicate which one you want to focus on first.  Even more important, please do whatever you can to get started on each problem; I'm sure you know at least some basics.

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Then what would "two intersecting lines" look like?  Draw the graph, or at least explain in words what the graph would look like.
5 0
3 years ago
Mrs. Gomes found that 40% of students at her high school take chemistry. She randomly surveys 12 students. What is the probabili
Virty [35]

Answer:

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3 years ago
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3.1 times 10 ^3 in ordinary form
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=3.1*10^3
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3 years ago
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