The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
Answer:
3- 5- 1
^ ^ ^
1 -5, 1,3 3,5
Step-by-step explanation:
Find the difference between each number:
-24/4 = -6
144/-24 = -6
The next number is multiplied by -6
You have the first 4 terms
5th term = -864 x -6 = 5184
6th term = 5184 x -6 = -31,104
7th term = -31,104 x -6 = 186,624
8th term = 186,624 x -6 = -1,119,744
Answer:
They will Markup the price by $19.76.
Step-by-step explanation:
Markup percent = 38%
Wholesale Price = $52
Markup price can be calculated by simply multiplying the wholesale price by 38% or 0.38.
so
Markup price = 38% of 52
= 38/100 × 52
= 0.38 × 52
= $19.76
Therefore, they will Markup the price by $19.76.
Answer:
-4
Step-by-step explanation:
16-20 = -4
