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LuckyWell [14K]
3 years ago
13

Can anyone help me on this question please.​

Mathematics
1 answer:
asambeis [7]3 years ago
4 0

Answer:

12

Step-by-step explanation:

quarterly means 4

3*4 = 12

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Point A is located at (4,7). The point is reflected the x-axis. It's image is located at
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Answer:    (4, -7)

Step-by-step explanation: Your reflecting it across the X axis so only the Y changes.

3 0
2 years ago
Solve each single-step equation. Show your work. -15+n=-9
Serggg [28]

Answer:

6

Step-by-step explanation:

-15+6 means it goes minus basically its 15-6(-15+6)=-9

3 0
2 years ago
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It costs 3 tickets to play a game at the fair. If you spent 21tickets on the game, which equation could you use to solve for the
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<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The correct option would be D. 3g = 21

As it is 3 tickets per game, the total number of tickets would be 3 multiplied by the number of games

This equation could then be rearranged to find the number of games.

<h3><u>✽</u></h3>

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5 0
2 years ago
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Please Answer <br><br> This is due by tomorrow night and I need help
labwork [276]

Answer:

AY = 16

IY = 9

FG = 30

PA = 24

Step-by-step explanation:

<em>The </em><em>centroid </em><em>of the triangle </em><em>divides each median</em><em> at the ratio </em><em>1: 2</em><em> from </em><em>the base</em>

Let us solve the problem

In Δ AFT

∵ Y is the centroid

∵ AP, TI, and FG are medians

→ By using the rule above

∴ Y divides AP at ratio 1: 2 from the base FT

∴ AY = 2 YP

∵ YP = 8

∴ AY = 2(8)

∴ AY = 16

∵ PA = AY + YP

∴ AP = 16 + 8

∴ AP = 24

∵ Y divides TI at ratio 1: 2 from the base FA

∴ TY = 2 IY

∵ TY = 18

∴ 18 = 2

→ Divide both sides by 2

∴ 9 = IY

∴ IY = 9

∵ Y divides FG at ratio 1:2 from the base AT

∴ FY = 2 YG

∵ FY = 20

∴ 20 = 2 YG

→ Divide both sides by 2

∴ 10 = YG

∴ YG = 10

∵ FG = YG + FY

∴ FG = 10 + 20

∴ FG = 30

5 0
2 years ago
Show that <br><br> Sin60 / cos60 = tan 60
Lerok [7]

Answer:

  • <em><u>sin60</u></em><em><u>=</u></em><em><u>opp\hyp</u></em>
  • <em><u>cos60</u></em><em><u>=</u></em><em><u>adja\hyp</u></em>
  • <em><u>tan60</u></em><em><u>=</u></em><em><u>opp\adj</u></em>
  • <em><u>sin60\cos60</u></em><em><u>=</u></em><em><u>tan60</u></em>
6 0
1 year ago
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