All categories

2 years ago

Divide using long division.

2 answers:

5 0

<h2>2. x2 - 2x - 8 - 3/x + 3 </h2><h2> </h2><h2>3. 2x2 + 5x +3 </h2><h2> </h2><h2>4. 2x2 + 3x + 1 </h2><h2> </h2><h2>5. x + 7 + 8/x + 2 </h2><h2> </h2><h2>6. 3x + 5 - 6/3x +5</h2><h2></h2><h2>plz mark as brainliest!!!</h2>

dedylja [7]2 years ago

4 0

Answer:

2. x2 - 2x - 8 - 3/x + 3

3. 2x2 + 5x +3

4. 2x2 + 3x + 1

5. x + 7 + 8/x + 2

6. 3x + 5 - 6/3x +5

Step-by-step explanation:

You might be interested in

I have the answer what is the steps

gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

Graph the following inequality:

Step2247 [10]

Answer: the intercept is love , the slope is you , dotted or solid is <3

Step-by-step explanation:

3 0

2 years ago

What is the slope-intercept form of a line that contains the point (0,3) and a slope =-2?

rosijanka [135]

Answer:

Step-by-step explanation:

-2 is in front of x so thats gonna be the slope

and +3 is the y-intercept

5 0

2 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

1 year ago

Whats slope intercept form for 2x- 5y=10

damaskus [11]

Answer:

y=-2/5x-2

Step-by-step explanation:

First, you put x to the other side of the equation so you get y alone, getting the equation of -5y=-2x+10. In order to just have y on one side, you need to divide the whole equation by -5. This leads to the final answer of y=-2/5x-2.

3 0

2 years ago