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marin [14]
3 years ago
10

El cuadruple de un número aumentado en 2 es menor igual a 50

Mathematics
1 answer:
Alchen [17]3 years ago
8 0

Answer:

4\cdot x + 2 \leq 50. La solución de la inecuación es todo número real menor o  igual a 12.

Step-by-step explanation:

El primer paso consiste en traducir la expresión en una expresión algebraica:

1) Un número: x

2) El cuádruplo de un número: 4\cdot x

3) El cuádruplo de un número y aumentado en 2: 4\cdot x + 2

4) El cuádruplo de un número y aumentado en 2 es menor o igual que 50: 4\cdot x + 2 \leq 50

Como siguiente paso, se resuelve la inecuación por métodos algebraicos:

1) 4\cdot x + 2 \leq 50 Dado

2) 4\cdot x \leq 48 Compatibilidad con la adición/Existencia del inverso aditivo/Modulatividad en la adición.

3) x \leq 12 Compatibilidad con la multiplicación/Existencia del inverso multiplicativo/Modulatividad en la multiplicación/Resultado.

En consecuencia, la solución de la inecuación es todo número real menor o  igual a 12.

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