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3 years ago

What is the 9th term of the geometric sequence 5 -25 125

Mathematics

1 answer:

OLga [1]3 years ago

7 0

Answer:

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term r : the common ratio

in this exercice : A1 =5 r = 125/-25=-25/5 = - 5 n = 9

A9=5×(-5)^(9-1) = 5×5^8 = 5^9 because : ((-5)^(8)= 5^8)

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Given that secant theta = Negative StartFraction 37 Over 12 EndFraction, what is the value of cotangent theta, for StartFraction

Iteru [2.4K]

$cot\theta$ $=\frac{12}{35}$

Step-by-step explanation:

$sec\theta =\frac{37}{12}$

⇔ $\frac{1}{cos \theta} =\frac{37}{12}$

⇔ $cos \theta = \frac{12}{37}$

we know that

$sin \theta = \sqrt{1-cos^2\theta}$

$sin\theta =\sqrt{1-(\frac{12}{37})^2 }$

$sin\theta=\sqrt{\frac{1225}{1369} }$

$sin\theta = \frac{35}{37}$

Therefore $cot\theta =\frac{cos\theta}{sin\theta}$ $=\frac{\frac{12}{37} }{\frac{35}{37} }$ $=\frac{12}{35}$ , for $\frac{\pi}{2}$

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PIT_PIT [208]

Answer:

<em>I think it didnt change</em>

Step-by-step explanation:

<em>Cause both areas from the line are the same and if it were to change the left would be diffrent from the right. So there i think it didnt change.</em>

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6 (3x-1)-10x. with work please :)

STatiana [176]

Hey there!
Let's break this expression into two parts:
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To solve the first part, we need to use the distributive property which states:
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Step-by-step explanation:

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