3 years ago

What is the 9th term of the geometric sequence 5 -25 125

Mathematics

1 answer:

OLga [1]3 years ago

7 0

Answer:

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term r : the common ratio

in this exercice : A1 =5 r = 125/-25=-25/5 = - 5 n = 9

A9=5×(-5)^(9-1) = 5×5^8 = 5^9 because : ((-5)^(8)= 5^8)

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