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Alina [70]
3 years ago
10

What is the value of the underlined digit 6035 (the 3 is underlined)

Mathematics
1 answer:
EastWind [94]3 years ago
6 0
The answer is 30 because the six is thousand and the three is in the tens place.
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Please help ! 20 pts please
Ksenya-84 [330]

The given ratios expresses the number of time a value is larger or smaller

than another value.

The correct responses are;

  • 3. <u>(B) 12 and 24</u>
  • 4. <u>(D) 6, 9, 21</u>
  • 5. \underline{(E) \ \displaystyle  \frac{11}{2}}
  • 6. \underline{(E) \ \displaystyle \frac{5}{14}}
  • 7. (B) \overline{EF} =<u> 6</u>, \overline{AC} = <u>9·√5</u>
  • 8. <u>(C) The values are equal</u>
  • 9. <u>(A) The value in column A is greater</u>

Reasons:

3. Given that the perimeter of the rectangle = 72

The ratio of the lengths of the sides = 1:2

Let <em>a</em> and <em>b</em> represent the sides, we have;

2·a + 2·b = 72

\displaystyle \frac{a}{b} = \mathbf{\frac{1}{2}}

Which gives;

2·a = b

2·a + 2·(2·a) = 72

6·a = 72

a = 72 ÷ 6 = 12

b = 2·a = 2 × 12 = 24

The lengths of the sides are; <u>(B) 12 and 24</u>

4. Extended ratio = 2:3:7

The perimeter = 36

The lengths of the sides are;

\displaystyle \frac{2}{2 + 3 + 7} \times 36 = \mathbf{6}

\displaystyle \frac{3}{2 + 3 + 7} \times 36 = \mathbf{9}

\displaystyle \frac{7}{2 + 3 + 7} \times 36 = \mathbf{21}

The lengths are; <u>(D) 6, 9, 21</u>

5. The given equation is presented as follows;

\displaystyle \frac{5}{x + 7} = \mathbf{\frac{3}{x + 2}}

5 × (x + 2) = 3 × (x + 7)

5·x + 10 = 3·x + 21

5·x - 3·x  = 21 - 10

2·x = 11

\displaystyle x = \mathbf{ \frac{11}{2}}

The correct option is; \displaystyle \underline{(E) \ \frac{11}{2}}

6. The width to length ratio is \displaystyle \mathbf{\frac{2.5}{7.0}}

The simplified ratio is therefore;

\displaystyle \frac{2.5}{7.0} =  \frac{2 \times 2.5}{2 \times 7.0} =  \mathbf{\frac{5}{14}}

The correct option is (E) \displaystyle \underline{(E) \ \frac{5}{14}}

7. The given ratio of the lengths is 3:1

Therefore;

\overline{BC}:\overline{EF} = 3:1

Which gives;

\displaystyle \mathbf{\frac{\overline{BC}}{\overline{EF}}} = \frac{3}{1}

\overline{BC} = 18

Therefore;

\displaystyle \frac{18}{\overline{EF}} = \frac{3}{1}

18 × 1 = 3 × \overline{EF}

\displaystyle \overline{EF} = \frac{18 \times 1}{3} = 6

\overline{EF} = 6

By Pythagorean theorem, we have;

\overline{DF}² = \mathbf{\overline{DE}}² + \mathbf{\overline{EF}}²

Which gives;

\overline{DF}² = 3² + 6² = 45

\overline{DF} = √(45) = 3·√5

Using the given ratio, we have;

\overline{AC} = 3 × \mathbf{\overline{DF}}

Which gives;

\overline{AC} = 3 × 3·√5 = 9·√5

\overline{AC} = 9·√5

The correct option is; (B) \overline{EF} =<u> 6</u>, \overline{AC} = <u>9·√5</u>

8. EF = 1, AB = 2

CD = 2, CE = 4

Therefore;

\displaystyle \mathbf{\frac{EF}{AB}} =\frac{1}{2}

\displaystyle \mathbf{\frac{CD}{CE}} =\frac{2}{4} = \frac{1}{2}

Which gives;

\displaystyle \frac{EF}{AB} =\displaystyle \mathbf{\frac{CD}{CE}}

<u>(C) The values are equal</u>

9. AC = 6, BE = 8

DF = 3, BD = 6

Column A

\displaystyle \frac{AC}{BE} =\displaystyle \mathbf{\frac{6}{8}} = \frac{3}{4}

Column B

\displaystyle \frac{DF}{BD} =\displaystyle \mathbf{\frac{3}{6}} = \frac{1}{2}

\displaystyle \frac{3}{4} > \mathbf{\frac{1}{2}}

Therefore;

Column A is greater than column B

<u>(A) The value in column A is greater</u>

Learn more about ratios here:

brainly.com/question/2774839

7 0
3 years ago
Where did i make a mistake?
bagirrra123 [75]

Answer:

they reflected over the y axis instead of the x.

6 0
3 years ago
Twelve divided by the sum of x and 2 equals the quotient of 4 and the difference of x and 2. Find x.
Marizza181 [45]

Answer:

Step-by-step explanation:

12/(x+2) = 4/(x-2)

Cross-multiply to get:

12x-24 = 4x+8

8x = 32

x = 4

7 0
4 years ago
Find the greatest common factor of 27 and 33.
Aneli [31]

Answer:

3

Step-by-step explanation:

26 and 33 both divisible by 3

4 0
3 years ago
Please help. I don't understand.
love history [14]

Answer: D

Step-by-step explanation:

The construction of a triangle tangent to the three sides would require the construction of the incircle.

3 0
3 years ago
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