Answer:
Explanation:
The observed frequency of the double crossovers (DCOs) is 20/1000, or 0.02. If there is no interference then this will be the same as the expected, which is just the product of the single crossover frequencies, that is, SCO frequency (a-b) x SCO freq. (b-c) = 0.02.
(a) Any combination of map distances whose product (a-b) x (b-c) = 0.02 is possible. However, three are most likely:
a 20 mu b 10 mu c
a 10 mu b 20 mu c
a 14.14 mu b 14.14 mu c
(b) The distances would be exactly the same.
(c) The expected number of DCO progeny would be 17.
Answer:
In the mentioned case, both the cells will start to perform replication of their DNA. In the case of G0, that is, the stationary phase, the mammalian cell can pass the restriction point with the supplementation of extracellular proliferation signal. While in the case of G1, which actually does not require any kind of external proliferation signal, as once the cell is in G1 phase, it is ready to go get the next phase. However, both the mammalian cells will cease or halt at G2 checkpoint.
The other answer is wrong. It would be pollution. Hope this helps you!
Answer:
B. It provides the code for the protein
Explanation:
Answer:
Salinity in an estuary varies according to one's location in the estuary, the daily tides, and the volume of fresh water flowing into the estuary. In estuaries, salinity levels are generally highest near the mouth of a river where the ocean water enters, and lowest upstream where freshwater flows in.
Explanation:
