If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
<span>
C.
His college savings account has a balance of $13,700.</span>
Answer:
86
Step-by-step explanation:
![48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2{1 (2 - 15÷3)}] \\ 8[ - 2.5{ (2 - 15÷3)}] \\ 8[ - 2.5{ ( - 13÷3)}] \\ 8[ - 2.5{ ( - 4.3)}] \\ 8[10.75 { }] \\ = 86](https://tex.z-dn.net/?f=48%C3%B76%20%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%20%7B4%20-%203%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B-52%20%C3%B72%7B1%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%282%20-%2015%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20-%2013%C3%B73%29%7D%5D%20%5C%5C%208%5B%20-%202.5%7B%20%28%20%20-%204.3%29%7D%5D%20%5C%5C%208%5B10.75%20%7B%20%7D%5D%20%5C%5C%20%20%3D%2086)
Invert and multiply
2/x*(3/(4x))
Then proceed to simplify
(You must simplify twice might I add)
Answer:
693
Step-by-step explanation:
7*9*11*3=693
