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lapo4ka [179]
3 years ago
11

Choose the inequality that could be used to solve the following problem.

Mathematics
2 answers:
Anit [1.1K]3 years ago
5 0
D...........................
Pie3 years ago
3 0
Answer:

3x = - 6

Step-by-step explanation:

Three times a number is at most negative six

3 times a number would be 3 times x, is means the equal sign (=)

3x = - 6

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Help me I need it asap<br>​
mel-nik [20]

Answer:53-6

Step-by-step explanation:

That’s the answer

5 0
3 years ago
Maya is taking her friends to a concert. Each ticket costs $25, and souvenir T-shirts are $12 each. There is a $4 service fee fo
evablogger [386]

Answer:

25x+12y+4 \leq 130

Step-by-step explanation:

Here, x represents the number of tickets and y represents the number of T-shirts.

As per the statement:

Each ticket costs $25,  and souvenir T-shirts are $12 each

⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y

It is also given that there is a $4 service fee for the entire purchase.

25x+12y+4

Since, she has $130

⇒25x+12y+4 \leq 130

Therefore, an inequality could you use to answer the problem is, 25x+12y+4 \leq 130

8 0
3 years ago
An investor has an account with stock from two different companies. Last year, her stock in Company A was worth $2690 and her st
Mrac [35]

Answer:

<h2> 14.7 %</h2>

Step-by-step explanation:

let us total the amount in her portfolio

Company A was worth $2690

Company B was worth $2980.

Total = $5670

when The stock in Company A decreases by 20%  she will have

$2690 *0.8=  $2152

Company A will worth $2152

when The stock in Company B decreases by 10%  she will have

$2980 *0.9=  $2682

Company A will worth  $2682

In all after the decline in are portfolio is $2152+$2682= $4834

the difference for the original amount in her investment is = $5670-$4834

= $836

The total percentage decrease in the investor's stock account

= (836/5670)*100= 0.147*100= 14.7 %

3 0
3 years ago
Assume that military aircraft use ejection seats designed for men weighing between 141.8 lb and 218 lb. If​ women's weights are
Mariulka [41]

Answer:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

Step-by-step explanation:

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(173.6,49.8)  

Where \mu=173.6 and \sigma=49.8

We are interested on this probability

P(141.8

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(141.8

And we can find this probability with this difference and using the normal standard table:

P(-0.639

Then the answer would be approximately 55.3% of women between the specifications. And that represent more than the half of women

8 0
3 years ago
Is there another number that has the prime factorization of 2x2x2x2x2x2x5x5x5x5x5x5?Explain.
NeX [460]
You have to put the number and count how many there are. Something like this.

7 0
3 years ago
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