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rewona [7]
3 years ago
11

The total amount of water a tank can hold is (14)1/2 gallons. Raul wants to find out how many (1)1/4 gallon buckets of water can

be used to fill the tank. Which expressions could be used to represent this scenario? Check all that apply.
Mathematics
2 answers:
Leokris [45]3 years ago
3 0
Y= (14)1/4 ÷ (1)1/4
Tank divide by bucket
Darya [45]3 years ago
3 0

Step-by-step explanation:

We have been given that the total amount of water a tank can hold is  14\frac{1}{2} gallons.

To find the number of 1\frac{1}{4} gallon buckets of water can be used to fill the tank we will divide the total amount of water in the tank by amount of water in one bucket.  

\text{Number of water buckets used}=\frac{\text{Total amount of water in the tank}}{\text{Amount of water in one bucket}}

Upon substituting our given values we will get,

\text{Number of water buckets used}=\frac{14\frac{1}{2} }{1\frac{1}{4}}

\text{Number of water buckets used}=\frac{\frac{29}{2} }{\frac{5}{4}}

Dividing a fraction with another fraction is same as multiplying the reciprocal of second fraction with the first fraction.  

\text{Number of water buckets used}={\frac{29}{2}}\times {\frac{4}{5}}

Therefore, all the above expressions can be used to find the number of 1\frac{1}{4} gallon buckets of water will be needed to fill the tank.  

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Ronald Fast Food randomly selected %20, percent of locations and asked the manager about the most popular meat. Of the locations
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Approximately 2%. The reason is if you choose 20% and only have four with beef as the most popular, and approximately the number of restaurants is 15.
8 0
3 years ago
a cell phone company test 95 cell phones and finds that seven of them have defects out of the 760 cell phones how many would you
suter [353]

Answer:

56

Step-by-step explanation:

simple ratio: 7/95 = x/760

first, calculate 7/95 which is 0.0736

next, multiply that by 760, which would be 56

6 0
3 years ago
The width of a container is 5 feet less than its height. Its length is 1 foot longer than its height. The volume of the containe
juin [17]

The height of container is 8 feet

<em><u>Solution:</u></em>

Let "w" be the width of container

Let "l" be the length of container

Let "h" be the height of container

The width of a container is 5 feet less than its height

Therefore,

width = height - 5

w = h - 5 ------ eqn 1

Its length is 1 foot longer than its height

length = 1 + height

l = 1 + h ---------- eqn 2

<em><u>The volume of container is given as:</u></em>

v = length \times width \times height

Given that volume of the container is 216 cubic feet

216 = l \times w \times h

Substitute eqn 1 and eqn 2 in above formula

216 = (1 + h) \times (h-5) \times h\\\\216 = (h+h^2)(h-5)\\\\216 = h^2-5h+h^3-5h^2\\\\216 = h^3-4h^2-5h\\\\h^3-4h^2-5h-216 = 0

Solve by factoring

(h-8)(h^2+4h+27) = 0

Use the zero factor principle

If ab = 0 then a = 0 or b = 0 ( or both a = 0 and b = 0)

Therefore,

h - 8 = 0\\\\h = 8

Also,

h^2+4h+27 = 0

Solve by quadratic equation formula

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

\mathrm{For\:} a=1,\:b=4,\:c=27:\quad h=\frac{-4\pm \sqrt{4^2-4\cdot \:1\cdot \:27}}{2\cdot \:1}

h = \frac{-4+\sqrt{4^2-4\cdot \:1\cdot \:27}}{2}=\frac{-4+\sqrt{92}i}{2}

Therefore, on solving we get,

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

<em><u>Thus solutions of "h" are:</u></em>

h = 8

h=-2+\sqrt{23}i,\:h=-2-\sqrt{23}i

"h" cannot be a imaginary value

Thus the solution is h = 8

Thus the height of container is 8 feet

8 0
3 years ago
Can an expert help with this
SVEN [57.7K]

The formula of an area of a circle:

A_O=\pi r^2

We have

r = 1.8 m

π ≈ 3.14

Substitute:

A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2

7 0
2 years ago
Can anyone help me?.
4vir4ik [10]
The third one is the correct answer
7 0
2 years ago
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