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4 years ago

HELP! CONFUSED ON WHAT TO DO!

1 answer:

4 0

Its If Kevin and Amanda continue to train until week 16, what will their times be? 6. Do you believe a linear model best represents the relationship of the time of the runners and the weeks that passed?(Hint: look at question 5). What do you think this says about problems in the real world? Justify your thoughts in 3-4 sentences. cause they are talking about minutes and per miles

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Simplify the expression state any excluded values 2a^2-4a+2 --------------- 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago

6x – 2 = 2х +8 ANSWER QUICKLY PLEASE

Soloha48 [4]

Answer: 2.5

Step-by-step explanation: subtract 2x from both sides and get 4x-2=8 so then add 2 on both sides to get 4x=10 and last step is to divide both sides by 4 which wild get you x=2.5

6 0

3 years ago

Read 2 more answers

Graph the inverse of the function.

Ghella [55]

Answer:

The graph of the inverse function is the same that the graph of the original function

Step-by-step explanation:

step 1

Find the equation of the function in the graph

Let

f(x) ---> the function in the graph

we know that

Is a linear function

take the points (0,6) and (6,0)

Find the slope of the linear function

$m=(0-6)/(6-0)\\m=-1$

Find the the equation of the linear function in slope intercept form

$f(x)=mx+b$

we have

$m=-1$

$b=6$ ---> the y-intercept is given

substitute

$f(x)=-x+6$

step 2

Find the inverse of the function f(x)

Let

y=f(x)

$y=-x+6$

Exchange the variables (x for y and y for x)

$x=-y+6$

Isolate the variable y

$y=-x+6$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=-x+6$

$f^{-1}(x)=f(x)$

In this problem the graph of the inverse function is the same that the graph of the original function

4 0

3 years ago

Adrian pays his niece $30 to babysit for 5 hours. Which expression models the change in the amount of Adrian’s cash each hour th

damaskus [11]

Both would be B! I hope this helps!

6 0

2 years ago

I will mark you as brainlis if you andwer this all.

dimaraw [331]

Answer: See below

Step-by-step explanation:

27. -(a-3)

28. (b-1)(b+3)

29. (c+4)(c+5)

30. d(d+5)

31. -(3/4)(2e-5)

Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.

For example: In problem 30:

(5d-20)/(d^2+d-20) * [??]/20d = 1/4

Factor:

(5(d-4)) d(d+5) = 1/4

(d-4)(d+5) 20d

The (d-4), d+5, and d terms cancel, leaving

5/20 = 1/4

7 0

2 years ago