$33.00 is the answer because $5.25 times 5= $26.25+ $6.25 = $33.00
Answer:
the number of times in a month the train must be used, so that the total monthly cost without the pass is the same as the total monthly cost with the pass, is b. 24 times
Step-by-step explanation:
in normal purchase, train ticket (A) = $2.00
using frequent pass,
frequent pass (P) = $18
train ticket using frequent pass (B) = $1.25
Now, let assume the number of times in a month the train must be used = M
so,
A x M = P + (B x M)
$2.00 x M = $18 + ($1.25 x M)
($2.00 x M) - ($1.25 x M) = $18
M x ($2.00 - $1.25) = $18
M = $18 : $0.75
M = 24
Thus, the number of times in a month the train must be used is 24 times
the answer is 81x thank youuuuu lol
it would be a, b, and c because if you look at the question and the answers, 3 of the four answers match the 3 of the 4 coordinates
