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a_sh-v [17]
4 years ago
13

Ella is testing out a new studying method and wants to know if it works. She decides to compare her spelling test scores from la

st week and this week. On last week's test, Ella spelled 16 out of the 20 words correctly. On this week's test, she spelled 13 out of the 15 words correctly. On which test did Ella get a higher ratio of correctly spelled words to total words?
Mathematics
1 answer:
Mademuasel [1]4 years ago
6 0

Answer:

it would take 4 days

Step-by-step explanation:BRAINLIEST PLEASE

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Use the remainder theorem to find the remainder of 2x^4 + x^2 - 10x -1 divided by x +2.
Svetllana [295]

Remainder Theorem says that if there is any Polynomial equation P(x), which is to be divided by (x - a) then remainder can be calculated by substituting value of a in equation P(x).  

2x^{4} +x^{2}-10x-1 = P(x)   divided by   (x+2)

Step 1: Find a

To find a we will have to convert (x+2) into (x - a) form

i.e.  (x+2) = (x - (-2))

therefore, a = -2

Step 2: Substitute value of a in P(x),

By substitution we get,

2(-2)^{4}+(-2)^{2}-10(-2)-1

= 2(16) + 4 +20 -1

= 32 +4 + 20 - 1

= 55 = Remainder

Hence, Remainder is 55.

8 0
3 years ago
Evaluate the expression:<br> 2 (m + 1) – n3 when m = -2 and n = 3
QveST [7]

Answer:

-15

Step-by-step explanation:

2 * (-4+2) = -6

-6 - 9 = -15

8 0
3 years ago
18x 24x greatest common factor
zzz [600]
18x and 24x.....GCF = 6x
4 0
3 years ago
Geometryyyy please help
svet-max [94.6K]

Answer:

x = 65

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which is true about the volume or surface area of these prisms?
pshichka [43]
Your answer is the second option: The surface area of B is greater than the surface area of A.

To find the surface area, I found the area of the three sides shown and added them together, and then multiplied the answer by 2, so:

B:
8 × 2 = 16
8 × 10 = 80
10 × 2 = 20
+
= 116
116 × 2 = 232 cm²

A:
5 × 8 = 40
5 × 4 = 20
8 × 4 = 32
+
= 92
92 × 2 = 184 cm²

So therefore B > A because 232 > 184

I hope this helps!
5 0
4 years ago
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